get script path

[hg]

Hi,

must I parse argv[0] to get it, or is there an easier way (that works under
Windows and *nix)?

Ex:

python /home/hg/test/test.py ==test.py #knows it is in /home/hg/test

Thanks,

hg

[hg]

Re: get script path

hg wrote:

Hi,
>
must I parse argv[0] to get it, or is there an easier way (that works
under Windows and *nix)?
>
Ex:
>
python /home/hg/test/test.py ==test.py #knows it is in /home/hg/test
>
Thanks,
>
hg

got it: os.path.dirname (sys.argv [0])

[Rob Wolfe]

Re: get script path


hg wrote:

Hi,
>
must I parse argv[0] to get it, or is there an easier way (that works under
Windows and *nix)?
>
Ex:
>
python /home/hg/test/test.py ==test.py #knows it is in /home/hg/test

IMHO it is easy enough:

>>dname, fname = os.path.split("/home/hg/test/test.py")
>>dname

'/home/hg/test'

--
HTH,
Rob

[hg]

Re: get script path

Rob Wolfe wrote:

>
hg wrote:

>Hi,
>>
>must I parse argv[0] to get it, or is there an easier way (that works
>under Windows and *nix)?
>>
>Ex:
>>
>python /home/hg/test/test.py ==test.py #knows it is in /home/hg/test

>
IMHO it is easy enough:
>

>>>dname, fname = os.path.split("/home/hg/test/test.py")
>>>dname

'/home/hg/test'
>
--
HTH,
Rob

thanks