search a part in a string

[rommeladres]

Completely newbie to scripting !! :
I would like to get the subject out of a mail message and put this in a seperate string:
mailMsg = mail.retr(i)[1]

example result of mailMsg is :

['Return-Path: <Louisette.Snoe kx@123.com>', 'Delivered-To: 3-marc.jonkers@45 6.com', 'From: "louisette snoekx" <Louisette.Snoe kx@123.com>', 'To: <marc.jonkers@4 56.com>', 'References: <20060919215507 .cvi40klhf1q888 4k@webmail.456. com>', 'Subject: Gelezen: workshop 15/10 essen', 'Date: Sun, 5 Nov 2006 22:05:53 +0100', .. etc]

I would like the string subject(i) to contain in this example 'Gelezen: workshop 15/10 essen'
I suppose it must be something like

for line in mailMsg:
if line.find('Subj ect:')
and then ???

[fuffens]

mailMsg = ['Return-Path: <Louisette.Snoekx@123.com>', 'Delivered-To: 3-marc.jonkers@456.com', 'From: "louisette snoekx" <Louisette.Snoekx@123.com>', 'To: <marc.jonkers@456.com>', 'References: <20060919215507.cvi40klhf1q8884k@webmail.456.com>', 'Subject: Gelezen: workshop 15/10 essen', 'Date: Sun, 5 Nov 2006 22:05:53 +0100']
subjectStr = 'Subject:'
subject = []
for item in mailMsg:
    if item.startswith(subjectStr):
        subject.append(item[len(subjectStr):].strip())
print subject

This will put the subject in a list assuming that mailMsg is a list of strings.

BR
/Fredrik

[rommeladres]

Thanks a lot !
This is aprox what I was looiking for!

The result of the print is for example [' something']
Is it possible to not showing the [' and the '] when printing ?

Second question:
if I do the same for the fromStr (mail comming from ...)
the print result is in this example :
"Louisette ,Snoekx "<Louisette.Sno ekx@123.com>
Here I just want to show :Louisette.Snoe kx@123.com when printing
so I only want what's between the < and >

Once again thanks a lot for your help !

[kudos]

Maybe something like this (if I understood the question correctly)

s = "\"Louisette ,Snoekx \"<Louisette.Snoekx@123.com>"
s =  ((((s.split("\""))[2]).split("<"))[1])
print s[:len(s)-1]

-kudos

Thanks a lot !
This is aprox what I was looiking for!

The result of the print is for example [' something']
Is it possible to not showing the [' and the '] when printing ?

Second question:
if I do the same for the fromStr (mail comming from ...)
the print result is in this example :
"Louisette ,Snoekx "<Louisette.Sno ekx@123.com>
Here I just want to show :Louisette.Snoe kx@123.com when printing
so I only want what's between the < and >

Once again thanks a lot for your help !

[rommeladres]

Maybe something like this (if I understood the question correctly)

s = "\"Louisette ,Snoekx \"<Louisette.Snoekx@123.com>"
s =  ((((s.split("\""))[2]).split("<"))[1])
print s[:len(s)-1]

-kudos

Kudos , thank you , but it doesn't seem to work.
Is there another way to strip everything in front of and including < ?
And is there another way to strip the last > ?

[bartonc]

Kudos , thank you , but it doesn't seem to work.
Is there another way to strip everything in front of and including < ?
And is there another way to strip the last > ?

There IS another way (there is almost always another way in Python).
Regular Expressions are what you need. Here is a link to a tutorial for using the re module:
http://www.amk.ca/python/howto/regex/.
Basically, (once you understand the syntax) you can tell a re.search() that you want everything that comes after "whatever" and is between "<" and ">" . Have fun and keep posting! Be sure to read the posting guidelines so that you know how to use code tags around the code in your posts. Thanks,
Barton

[bartonc]

Thanks a lot !
This is aprox what I was looiking for!

The result of the print is for example [' something']
Is it possible to not showing the [' and the '] when printing ?

Second question:
if I do the same for the fromStr (mail comming from ...)
the print result is in this example :
"Louisette ,Snoekx "<Louisette.Sno ekx@123.com>
Here I just want to show :Louisette.Snoe kx@123.com when printing
so I only want what's between the < and >

Once again thanks a lot for your help !

1)

 
mailMsg = ['Return-Path: <Louisette.Snoekx@123.com>', 'Delivered-To: 3-marc.jonkers@456.com', 'From: "louisette snoekx" <Louisette.Snoekx@123.com>', 'To: <marc.jonkers@456.com>', 'References: <20060919215507.cvi40klhf1q8884k@webmail.456.com>', 'Subject: Gelezen: workshop 15/10 essen', 'Date: Sun, 5 Nov 2006 22:05:53 +0100']
subjectStr = 'Subject:'
subject = []
for item in mailMsg:
	if item.startswith(subjectStr):
		subject.append(item[len(subjectStr):].strip())
for item in subject:
	print item

2)

 
fromaddress = ""
for item in mailMsg: 
	if item.startswith("From:"):
		i = item.find("<") + 1
		j = item.find(">", i)
		fromaddress = item[i:j]
print fromaddress

As I said, there's (almost) always another way in python.

[bartonc]

here's how to get help at the python prompt:

 
>>> help(str.find)
Help on method_descriptor: 
 
find(...)
	S.find(sub [,start [,end]]) -> int
 
	Return the lowest index in S where substring sub is found,
	such that sub is contained within s[start,end]. Optional
	arguments start and end are interpreted as in slice notation.
 
	Return -1 on failure.

[rommeladres]

Thanks a lot bartonc !
Now it works !!

[bartonc]

Thanks a lot bartonc !
Now it works !!

You are very welcome. Keep posting here on the python forum,
Barton