To Kill a Process that is Accepting Connection on Socket

[mumebuhi]

I removed my previous post about this topic because I apparently have
pasted the wrong code. Sorry for the confusion and thanks for being
patient.

I am having problem to kill the following script completely. The script
basically does the following. The main thread creates a new thread,
which does a completely useless thing, and then starts excepting for a
connection via socket.

# start
import pickle
import signal
import simplejson
import socket
import sys
import threading
import time

counter = 0

class WorkerThread(th reading.Thread) :
def run(self):
global counter
while True:
counter += 1
time.sleep(10)

worker_thread = WorkerThread()
worker_thread.s tart()

server = socket.socket(s ocket.AF_INET, socket.SOCK_STR EAM)
server.bind(('' , 2727))
server.listen(2 )

def cleanup(signal, frame):
print "die now"
worker_thread.j oin(1)
server.shutdown (socket.SHUT_RD WR)
sys.exit(0)
signal.signal(s ignal.SIGINT, cleanup)

while True:
channel, details = server.accept()
stats = { 'key': "value" }
s = simplejson.dump s(stats)
channel.send(s)
channel.close()
# end

The way I can think of right now is to kill the script using Ctrl+C.
Hence, the signal handler in the code. However, the interpreter
complains:
$ python ex_server.py
die now
Traceback (most recent call last):
File "ex_server. py", line 33, in ?
channel, details = server.accept()
File "/usr/lib/python2.4/socket.py", line 169, in accept
sock, addr = self._sock.acce pt()
File "ex_server. py", line 28, in cleanup
server.shutdown (socket.SHUT_RD WR)
File "<string>", line 1, in shutdown
socket.error: (128, 'Transport endpoint is not connected')

Does anybody know a better way to do this?

Thank you.

Buhi