>>y
[116, 114, 121, 32, 116, 104, 105, 115]
'try this'
What is an efficient way to do this if y is much longer?
(A numpy solution is fine.)
Thanks,
Alan Isaac
[116, 114, 121, 32, 116, 104, 105, 115]
>>z=''.join(chr (yi) for yi in y)
>>z
>>z
What is an efficient way to do this if y is much longer?
(A numpy solution is fine.)
Thanks,
Alan Isaac
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