urllib.urlopen: Errno socket error

[kgrafals@gmail.com]

Hi,

I'm just trying to read from a webpage with urllib but I'm getting
IOErrors. This is my code:

import urllib
sock = urllib.urlopen( "http://www.google.com/")

and this is the error:

Traceback (most recent call last):
File "<pyshell#5 >", line 1, in <module>
sock = urllib.urlopen( "http://www.google.com/")
File "C:\Python25\li b\urllib.py", line 82, in urlopen
return opener.open(url )
File "C:\Python25\li b\urllib.py", line 190, in open
return getattr(self, name)(url)
File "C:\Python25\li b\urllib.py", line 325, in open_http
h.endheaders()
File "C:\Python25\li b\httplib.py", line 856, in endheaders
self._send_outp ut()
File "C:\Python25\li b\httplib.py", line 728, in _send_output
self.send(msg)
File "C:\Python25\li b\httplib.py", line 695, in send
self.connect()
File "C:\Python25\li b\httplib.py", line 679, in connect
raise socket.error, msg
IOError: [Errno socket error] (10060, 'Operation timed out')

I'm behind my company's firewall. Would that cause a problem? If it
does, How do I get around it?

[Salvatore]

Re: urllib.urlopen: Errno socket error

Hello,

Try to increase the time out : socket.settimeo ut(n)
and catch the timeout error when it occurs

Regards



kgrafals@gmail. com a écrit :

Hi,
>
I'm just trying to read from a webpage with urllib but I'm getting
IOErrors. This is my code:
>
import urllib
sock = urllib.urlopen( "http://www.google.com/")
>
and this is the error:
>
Traceback (most recent call last):
File "<pyshell#5 >", line 1, in <module>
sock = urllib.urlopen( "http://www.google.com/")
File "C:\Python25\li b\urllib.py", line 82, in urlopen
return opener.open(url )
File "C:\Python25\li b\urllib.py", line 190, in open
return getattr(self, name)(url)
File "C:\Python25\li b\urllib.py", line 325, in open_http
h.endheaders()
File "C:\Python25\li b\httplib.py", line 856, in endheaders
self._send_outp ut()
File "C:\Python25\li b\httplib.py", line 728, in _send_output
self.send(msg)
File "C:\Python25\li b\httplib.py", line 695, in send
self.connect()
File "C:\Python25\li b\httplib.py", line 679, in connect
raise socket.error, msg
IOError: [Errno socket error] (10060, 'Operation timed out')
>
I'm behind my company's firewall. Would that cause a problem? If it
does, How do I get around it?

[kgrafals@gmail.com]

Re: urllib.urlopen: Errno socket error

Hi Salvatore,

Even if I catch the exceptions in a loop it goes on forever.

- ken

[kgrafals@gmail.com]

Re: urllib.urlopen: Errno socket error

Dennis,

I tried a ProxyHandler with the following code ...

proxy_support = urllib2.ProxyHa ndler({})
opener = urllib2.build_o pener(proxy_sup port)
urllib2.install _opener(opener)

.... but it's giving me the same result.

Then I tried to tunnel using code from ...

http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/213238

.... but it too gave me an error ...

Traceback (most recent call last):
File "<pyshell#7 >", line 1, in <module>
tunnel.run(tunn el_this)
File "C:/Python25/My Python/PyTunnel.py", line 124, in run
Threads.append( thread_it(tid=0 ,proxy=self.get _proxy(),\
File "C:/Python25/My Python/PyTunnel.py", line 81, in get_proxy
proxy.connect(( self._phost,sel f._pport))
File "<string>", line 1, in connect
gaierror: (11001, 'getaddrinfo failed')

[frifri007]

Re: urllib.urlopen: Errno socket error


kgrafals@gmail. com a écrit :

Hi,
>
I'm just trying to read from a webpage with urllib but I'm getting
IOErrors. This is my code:
>
import urllib
sock = urllib.urlopen( "http://www.google.com/")
>
and this is the error:
>
Traceback (most recent call last):
File "<pyshell#5 >", line 1, in <module>
sock = urllib.urlopen( "http://www.google.com/")
File "C:\Python25\li b\urllib.py", line 82, in urlopen
return opener.open(url )
File "C:\Python25\li b\urllib.py", line 190, in open
return getattr(self, name)(url)
File "C:\Python25\li b\urllib.py", line 325, in open_http
h.endheaders()
File "C:\Python25\li b\httplib.py", line 856, in endheaders
self._send_outp ut()
File "C:\Python25\li b\httplib.py", line 728, in _send_output
self.send(msg)
File "C:\Python25\li b\httplib.py", line 695, in send
self.connect()
File "C:\Python25\li b\httplib.py", line 679, in connect
raise socket.error, msg
IOError: [Errno socket error] (10060, 'Operation timed out')
>
I'm behind my company's firewall. Would that cause a problem? If it
does, How do I get around it?

See the documentation for urllib.urlopen:

"""
In a Windows environment, if no proxy environment variables are set,
proxy settings are obtained from the registry's Internet Settings
section.
"""
Remove Proxy configuration under IE and try again
(don't use Ie anymore ;0)