Python ord() function.

[karthikr_04]

Hello ,
I am new and I was stuck with the ord function.
When i passed the value like this it gave me proper o/p:
>>ord('\x16')
22
but when i concatenate '\x' and 16 the length of the string becomes 4 and it gives error.What's the method to convert it into ASCII like the one above for a string.

[ghostdog74]

Hello ,
I am new and I was stuck with the ord function.
When i passed the value like this it gave me proper o/p:
>>ord('\x16')
22
but when i concatenate '\x' and 16 the length of the string becomes 4 and it gives error.What's the method to convert it into ASCII like the one above for a string.

it's hex representation
eg. you can try ord('a'). It gives you 97. looking at ascii chart, 'a' is hex 61. so if you do ord('\x61'), it will also give you 97.

[bartonc]

More precisely, "\x" is an escape operator or hex conversion and the number following it is its operand and must be a hex number. If you try:

>>> b='\x'+'0a'
ValueError: invalid \x escape

you may begin to see.

[bartonc]

If you really need your program to convert a string which represents a hex number, you can use:

>>> eval("0x0a")
10