Need help with python. Hex converting.

[lazyjacket]

I've just started with python, and need some help.

Decimal = raw_input('Ente r your decimal number: ')
hex = hex()
print "Your Hexadecimal is " + hex

is the code. and the problem is that i cant get number im punching in the raw_input field to appear in the () after the text. this is the error, Enter your decimal number: 110101
Traceback (most recent call last):
File "C:\Python24\py thon\hex.py", line 2, in ?
hex = hex()
TypeError: hex() takes exactly one argument (0 given).. does any one here, know what i need to do to acomplish my goal?

[ghostdog74]

I've just started with python, and need some help.

Decimal = raw_input('Ente r your decimal number: ')
hex = hex()
print "Your Hexadecimal is " + hex

is the code. and the problem is that i cant get number im punching in the raw_input field to appear in the () after the text. this is the error, Enter your decimal number: 110101
Traceback (most recent call last):
File "C:\Python24\py thon\hex.py", line 2, in ?
hex = hex()
TypeError: hex() takes exactly one argument (0 given).. does any one here, know what i need to do to acomplish my goal?

the error message says it all.
you need an argument to hex()....eg hex(some_argume nt)...
i guess you know what to do now..

[lazyjacket]

the error message says it all.
you need an argument to hex()....eg hex(some_argume nt)...
i guess you know what to do now..

the problem is that i dont what argument to use, just started up with python (total noob)

[ghostdog74]

the problem is that i dont what argument to use, just started up with python (total noob)

Decimal = raw_input('Ente r your decimal number: ')
hex = hex()
print "Your Hexadecimal is " + hex

you want to change Decimal to hex , right?
so the argument to hex is Decimal...like this hex(Decimal) .