split a line, respecting double quotes

[Jim]

Is there some easy way to split a line, keeping together double-quoted
strings?

I'm thinking of
'a b c "d e"' --['a','b','c','d e']
.. I'd also like
'a b c "d \" e"' --['a','b','c','d " e']
which omits any s.split('"')-based construct that I could come up with.

Thank you,
JIm

[faulkner]

Re: split a line, respecting double quotes

import re
re.findall('\". *\"|\S+', raw_input())

Jim wrote:

Is there some easy way to split a line, keeping together double-quoted
strings?
>
I'm thinking of
'a b c "d e"' --['a','b','c','d e']
. I'd also like
'a b c "d \" e"' --['a','b','c','d " e']
which omits any s.split('"')-based construct that I could come up with.
>
Thank you,
JIm

[vbgunz]

Re: split a line, respecting double quotes

Jim wrote:

Is there some easy way to split a line, keeping together double-quoted
strings?

using the re module I find this to probably be the easiest but in no
way is this gospel :)

import re
rex = re.compile(r'(" .*?"|\S)')
sub = 'a b c "d e"'
res = [x for x in re.split(rex, sub) if not x.isspace()][1:-1]
print res # -['a', 'b', 'c', '"d e"']

basically import the re module, compile a pattern, identify a string,
create a list comprehension with a filter, slice out the result and
print to screen. I hope this helps.

[faulkner]

Re: split a line, respecting double quotes

sorry, i didn't read all your post.
def test(s):
res = ['']
in_dbl = False
escaped = False
for c in s:
if in_dbl:
if escaped:
res[-1] += c
if c != '\\':
escaped = False
else:
res[-1] += c
if c == '\\':
escaped = True
elif c == '"':
res.append('')
in_dbl = False
elif c == ' ':
res.append('')
elif c == '"':
res.append('')
res[-1] += c
in_dbl = True
else:
res[-1] += c
while '' in res:
res.remove('')
return res

faulkner wrote:

import re
re.findall('\". *\"|\S+', raw_input())
>
Jim wrote:

Is there some easy way to split a line, keeping together double-quoted
strings?

I'm thinking of
'a b c "d e"' --['a','b','c','d e']
. I'd also like
'a b c "d \" e"' --['a','b','c','d " e']
which omits any s.split('"')-based construct that I could come up with.

Thank you,
JIm

[Steven Bethard]

Re: split a line, respecting double quotes

Jim wrote:

Is there some easy way to split a line, keeping together double-quoted
strings?
>
I'm thinking of
'a b c "d e"' --['a','b','c','d e']
. I'd also like
'a b c "d \" e"' --['a','b','c','d " e']
which omits any s.split('"')-based construct that I could come up with.

>>import shlex
>>shlex.split(' a b c "d e"')

['a', 'b', 'c', 'd e']

>>shlex.split(r 'a b c "d \" e"')

['a', 'b', 'c', 'd " e']

Note that I had to use a raw string in the latter case because otherwise
there's no real backslash in the string::

>>'a b c "d \" e"'

'a b c "d " e"'

>>r'a b c "d \" e"'

'a b c "d \\" e"'

STeVe

[vbgunz]

Re: split a line, respecting double quotes

Is there some easy way to split a line, keeping together double-quoted

strings?

import re
rex = re.compile(r'(" .*?"|\S)')
sub = 'a b c "d e"'
res = [x for x in re.split(rex, sub) if not x.isspace()][1:-1]
print res # -['a', 'b', 'c', '"d e"']

instead of slicing the result out, you use this too:
res = [x for x in re.split(rex, sub) if x[0:].strip()]

[Jim]

Re: split a line, respecting double quotes


Jim wrote:

Is there some easy way to split a line, keeping together double-quoted
strings?

Thank you for the replies.

Jim

[Sion Arrowsmith]

Re: split a line, respecting double quotes

Jim <jhefferon@smcv t.eduwrote:

>Is there some easy way to split a line, keeping together double-quoted
>strings?
>
>I'm thinking of
'a b c "d e"' --['a','b','c','d e']
>. I'd also like
'a b c "d \" e"' --['a','b','c','d " e']
>which omits any s.split('"')-based construct that I could come up with.

>>csv.reader(St ringIO.StringIO ('a b c "d e"'), delimiter=' ').next()

['a', 'b', 'c', 'd e']

It can't quite do the second one, but:

>>csv.reader(St ringIO.StringIO ('a b c "d "" e"'), delimiter=' ').next()

['a', 'b', 'c', 'd " e']
isn't far off.

On the other hand, it's kind of a stupid solution. I'd really go with
shlex as someone suggested up thread.

--
\S -- siona@chiark.gr eenend.org.uk -- http://www.chaos.org.uk/~sion/
___ | "Frankly I have no feelings towards penguins one way or the other"
\X/ | -- Arthur C. Clarke
her nu becomeþ se bera eadward ofdun hlæddre heafdes bæce bump bump bump

[Raymond Hettinger]

Re: split a line, respecting double quotes

Sion Arrowsmith wrote:

>csv.reader(Str ingIO.StringIO( 'a b c "d "" e"'), delimiter=' ').next()

['a', 'b', 'c', 'd " e']
isn't far off.
>
On the other hand, it's kind of a stupid solution.

IMO, this solution is on the right track.
FWIW, the StringIO wrapper is unnecessary.
Any iterable will do:
reader(['a b c "d e"'], delimiter=' ')


Raymond