Python question

[Harry]

Hi All,
It is nice to join the python group. Can someone please help me with
a python question?
I have the following object which is like a list of tuples
What command do I use to get the value corresponding to 'min'?
This object seems to be non-indexable


row= [('name', 'x1'), ('min', 15.449041129349 528), ('max',
991.63378182456 29), ('range', 976.18474069521 335), ('mean',
496.82174193958 127), ('stddev', 304.78275004920 454), ('variance',
92892.524727555 894), ('mode', '46.5818482111' ), ('unique_count' , '99'),
('count', 99.0), ('count_missing ', 0.0), ('sum_weight', 99.0)]

Thanks,
Harry

[Erik Max Francis]

Re: Python question

Harry wrote:
[color=blue]
> It is nice to join the python group. Can someone please help me with
> a python question?
> I have the following object which is like a list of tuples
> What command do I use to get the value corresponding to 'min'?
> This object seems to be non-indexable
>
>
> row= [('name', 'x1'), ('min', 15.449041129349 528), ('max',
> 991.63378182456 29), ('range', 976.18474069521 335), ('mean',
> 496.82174193958 127), ('stddev', 304.78275004920 454), ('variance',
> 92892.524727555 894), ('mode', '46.5818482111' ), ('unique_count' , '99'),
> ('count', 99.0), ('count_missing ', 0.0), ('sum_weight', 99.0)][/color]

Iterating would be the best way. There are shorter ways of writing it,
for instance with list comprehensions, but it's still iteration::

for key, value in row:
if key == 'min':
print value
break

or::

results = [v for k, v in row if k == 'min']
print results[0]

Another way, if you plan to access this same data structure in this way
multiple times before moving on to the next one, would be to turn it
into a dictionary first::

d = dict(row)
print d['min']

Note that all of these solutions assume that the key you want is indeed
in there. If it might not be, then you'll have to gracefully handle errors.

--
Erik Max Francis && max@alcyone.com && http://www.alcyone.com/max/
San Jose, CA, USA && 37 20 N 121 53 W && AIM erikmaxfrancis
Divide the fire, and you will the sooner put it out.
-- Publilius Syrus

[Bruno Desthuilliers]

Re: Python question

Harry wrote:[color=blue]
> Hi All,[/color]
(snip)[color=blue]
> I have the following object which is like a list of tuples[/color]
[color=blue]
> row= [('name', 'x1'), ('min', 15.449041129349 528), ('max',
> 991.63378182456 29), ('range', 976.18474069521 335), ('mean',
> 496.82174193958 127), ('stddev', 304.78275004920 454), ('variance',
> 92892.524727555 894), ('mode', '46.5818482111' ), ('unique_count' , '99'),
> ('count', 99.0), ('count_missing ', 0.0), ('sum_weight', 99.0)][/color]

FWIW, it *is* a list of tuples.
[color=blue]
> What command[/color]

<ot> What's a 'command' ? </ot>
[color=blue]
> do I use to get the value corresponding to 'min'?[/color]
(see below...)
[color=blue]
> This object seems to be non-indexable[/color]

It is - just like any other list. Try :
print row[0]
print row[1]
# etc...

Now if you want keyword access, try this:
print dict(row)['min']



--
bruno desthuilliers
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in 'onurb@xiludom. gro'.split('@')])"