re question

[Daniel Schüle]

Hello re gurus,

I wrote this pattern trying to get the "name" and the "content" of VHDL
package
I know that the file is a valid VHDL code, so actually there is no need to
perform
validation after 'end' token is found, but since it works fine I don't want
to touch it.

this is the pattern

pattern =
re.compile(r'^\ s*package\s+(?P <name>\w+)\s+is \s+(?P<content> .*?)\s+end(\s+p ackage)?(\s+(?P =name))?\s*;',
re.DOTALL | re.MULTILINE | re.IGNORECASE)

and the problem is that
package TEST is xyz end;
works but
package TEST123 is xyz end;
fails

\w is supposed to match [a-zA-Z0-9_] so I don't understand why numbers and
undescore let the pattern fail?
(there is a slight suspicion that it may be a re bug)

I also tried this pattern with the same results

pattern =
re.compile(r'^\ s*package\s+(?P <name>.+?)\s+is \s+(?P<content> .*?)\s+end(\s+p ackage)?(\s+(?P =name))?\s*;',
re.DOTALL | re.MULTILINE | re.IGNORECASE)

something must be wrong with (?P<name>\w+) inside the main pattern

thanks in advance

--
Daniel

[Marc 'BlackJack' Rintsch]

Re: re question

In <e7gq1d$clo$1@n ews2.rz.uni-karlsruhe.de>, Daniel Schüle wrote:
[color=blue]
> this is the pattern
>
> pattern =
> re.compile(r'^\ s*package\s+(?P <name>\w+)\s+is \s+(?P<content> .*?)\s+end(\s+p ackage)?(\s+(?P =name))?\s*;',
> re.DOTALL | re.MULTILINE | re.IGNORECASE)
>
> and the problem is that
> package TEST is xyz end;
> works but
> package TEST123 is xyz end;
> fails[/color]

For me both work:

In [11]:pattern = (
t>.*?)\s+end(\s +package)?(\s+( ?P=name))?\s*;' , )\s+is\s+(?P<co nten
.11.:re.DOTALL | re.MULTILINE | re.IGNORECASE))

In [12]:pattern.match( 'package TEST is xyz end;')
Out[12]:<_sre.SRE_Matc h object at 0x405b1650>

In [13]:pattern.match( 'package TEST123 is xyz end;')
Out[13]:<_sre.SRE_Matc h object at 0x405b15f8>

I have copy and pasted you code.

For debugging re's in Python you might take a
look at http://kodos.sourceforge.net/

Ciao,
Marc 'BlackJack' Rintsch

[Daniel Schüle]

Re: re question

Hi

[...]

hm, that's wired
I just tried it in python shell and it works but same code as script file
fails

for anyone who want to see for himself

# package.vhd file
bash % cat package.vhd
library ieee;
use ieee.std_logic_ 1164.all;

package TEST123 is
constant BASE
End Package Test;


# parser.py
bash % cat parser.py
#!/usr/bin/env python

import sys, re

reflags = re.DOTALL | re.MULTILINE | re.IGNORECASE

pattern =
re.compile(r'^\ s*package\s+(?P <name>\w+)\s+is \s+(?P<content> .*?)\s+end(\s+p ackage)?(\s+(?P =name))?\s*;',
reflags)

class PackageParser(o bject):
def __init__(self, filename):
self.package = file(filename). read()
def parse(self):
return pattern.search( self.package)

if __name__ == "__main__":
p = PackageParser(" package.vhd")
m = p.parse()
if m is None:
print "nothing"
sys.exit(1)
print m.group("conten t")
print m.group("name")


# testing
bash % ./parser.py
nothing

ps:[color=blue][color=green][color=darkred]
>>> sys.version[/color][/color][/color]
'2.4.2 (#2, Mar 3 2006, 13:32:59) \n[GCC 3.2.2 20030222 (Red Hat Linux
3.2.2-5)]'

Regards, Daniel

[Paul McGuire]

Re: re question

Shouldn't

End Package Test;

read:

End Package Test123;


-- Paul

[Daniel Schüle]

Re: re question


"Paul McGuire" <ptmcg@austin.r r._bogus_.com> schrieb im Newsbeitrag
news:QeUmg.2819 7$vU.25824@torn ado.texas.rr.co m...[color=blue]
> Shouldn't
>
> End Package Test;
>
> read:
>
> End Package Test123;
>
>
> -- Paul[/color]

yes it must :)
my mistake

thx