Simple script to make .png thumbnails from .zip archive...

[K P S]

Hi.
I'm looking for a small script that will take a .zip archive and pull
the first .jpg from the archive and convert it to a .png.

The reason for this is I want to have tuhmbnails for these archives in
nautilus under gnome. I would like something similar to the following
code, which will pull a thumbnail from an openoffice.org (oasis)
document. What I want is a little more involved, I guess, since I
don't know the name of the file (for the zip.read command), and I need
to convert the file from .jpg to .png once I get it. Any help would be
appreciated. Including a pointer to a web page of a manual with
examples. :-)

#!/usr/bin/python

import zipfile
import sys
import gnomevfs

inURL=gnomevfs. get_local_path_ from_uri(sys.ar gv[1])
outURL=sys.argv[2]

zip=zipfile.Zip File(inURL,mode ="r")
picture=zip.rea d("Thumbnails/thumbnail.png")
thumbnail=open( outURL,"w")
thumbnail.write (picture)
thumbnail.write ("/n")
zip.close()
thumbnail.close ()

[hdante]

Re: Simple script to make .png thumbnails from .zip archive...

Hi,

I don't know zipfile by heart, but python official documentation is
always good ( docs.python.org ). You need a loop in the file list like
this:

for file in zip:
process(file)

Unfortunatelly, there are too many ways to create a thumbnail from an
image. I'll cite one, using the "python image" external module, that
I've found to be very easy:

import Image
def process(file):
try:
image = Image.open(file )
image.thumbnail ((128,128), Image.ANTIALIAS )
image.save (file + '.thumb.png')
except:
print 'Skipping file', file

Links:
http://docs.python.org/lib/lib.html - Python Library Reference
http://www.pythonware.com/library/pi...book/image.htm - The Image
Module

K P S wrote:[color=blue]
> Hi.
> I'm looking for a small script that will take a .zip archive and pull
> the first .jpg from the archive and convert it to a .png.
>
> The reason for this is I want to have tuhmbnails for these archives in
> nautilus under gnome. I would like something similar to the following
> code, which will pull a thumbnail from an openoffice.org (oasis)
> document. What I want is a little more involved, I guess, since I
> don't know the name of the file (for the zip.read command), and I need
> to convert the file from .jpg to .png once I get it. Any help would be
> appreciated. Including a pointer to a web page of a manual with
> examples. :-)
>
> #!/usr/bin/python
>
> import zipfile
> import sys
> import gnomevfs
>
> inURL=gnomevfs. get_local_path_ from_uri(sys.ar gv[1])
> outURL=sys.argv[2]
>
> zip=zipfile.Zip File(inURL,mode ="r")
> picture=zip.rea d("Thumbnails/thumbnail.png")
> thumbnail=open( outURL,"w")
> thumbnail.write (picture)
> thumbnail.write ("/n")
> zip.close()
> thumbnail.close ()[/color]

[Scott David Daniels]

Re: Simple script to make .png thumbnails from .zip archive...

hdante wrote:[color=blue]
> .... there are too many ways to create a thumbnail from an
> image. I'll cite one, using the "python image" external module, that
> I've found to be very easy:
>
> import Image
> def process(file):
> try:
> image = Image.open(file )
> image.thumbnail ((128,128), Image.ANTIALIAS )
> image.save (file + '.thumb.png')
> except:
> print 'Skipping file', file
>
> Links:
> http://docs.python.org/lib/lib.html - Python Library Reference
> http://www.pythonware.com/library/pi...book/image.htm - The Image
> Module[/color]

That, by the way, is the "PIL" library that you'll see a lot about --
The Python Imaging Library that the effbot is justly proud of. You
won't do better than that.

--Scott David Daniels
scott.daniels@a cm.org

[K P S]

Re: Simple script to make .png thumbnails from .zip archive...

Thanks a lot.
I'm really new to python, and haven't coded in over a decade, so
please be patient. :-)

I'm able to read a .jpg from a .zip archive, but can't seem to
manipulate it. If I do this:

zip=zipfile.Zip File(inURL,mode ="r")
picture=zip.rea d("00.jpg")

I get the image, but it is of "type" ZipFile. How can I change it to
type Image? Or am I thinking about this in the wrong way? I would
like to follow this with something like:

picture.thumbna il((128, 128), Image.ANTIALIAS )

But obviously I can't do this directly. What am I missing?

hdante wrote:[color=blue]
> Hi,
>
> I don't know zipfile by heart, but python official documentation is
> always good ( docs.python.org ). You need a loop in the file list like
> this:
>
> for file in zip:
> process(file)
>
> Unfortunatelly, there are too many ways to create a thumbnail from an
> image. I'll cite one, using the "python image" external module, that
> I've found to be very easy:
>
> import Image
> def process(file):
> try:
> image = Image.open(file )
> image.thumbnail ((128,128), Image.ANTIALIAS )
> image.save (file + '.thumb.png')
> except:
> print 'Skipping file', file
>
> Links:
> http://docs.python.org/lib/lib.html - Python Library Reference
> http://www.pythonware.com/library/pi...book/image.htm - The Image
> Module
>
> K P S wrote:[color=green]
> > Hi.
> > I'm looking for a small script that will take a .zip archive and pull
> > the first .jpg from the archive and convert it to a .png.
> >
> > The reason for this is I want to have tuhmbnails for these archives in
> > nautilus under gnome. I would like something similar to the following
> > code, which will pull a thumbnail from an openoffice.org (oasis)
> > document. What I want is a little more involved, I guess, since I
> > don't know the name of the file (for the zip.read command), and I need
> > to convert the file from .jpg to .png once I get it. Any help would be
> > appreciated. Including a pointer to a web page of a manual with
> > examples. :-)
> >
> > #!/usr/bin/python
> >
> > import zipfile
> > import sys
> > import gnomevfs
> >
> > inURL=gnomevfs. get_local_path_ from_uri(sys.ar gv[1])
> > outURL=sys.argv[2]
> >
> > zip=zipfile.Zip File(inURL,mode ="r")
> > picture=zip.rea d("Thumbnails/thumbnail.png")
> > thumbnail=open( outURL,"w")
> > thumbnail.write (picture)
> > thumbnail.write ("/n")
> > zip.close()
> > thumbnail.close ()[/color][/color]

[Ant]

Re: Simple script to make .png thumbnails from .zip archive...

Try adapting the other posters example with something like:

import Image, StringIO
zip=zipfile.Zip File(inURL,mode ="r")
picture=zip.rea d("00.jpg")
image = Image.open(Stri ngIO(picture))
image.thumbnail ((128,128), Image.ANTIALIAS )
image.save (file + '.thumb.png')

I haven't tested it, but something like this should work.

[Fredrik Lundh]

Re: Simple script to make .png thumbnails from .zip archive...

K P S wrote:
[color=blue]
> I'm able to read a .jpg from a .zip archive, but can't seem to
> manipulate it. If I do this:
>
> zip=zipfile.Zip File(inURL,mode ="r")
> picture=zip.rea d("00.jpg")
>
> I get the image, but it is of "type" ZipFile.[/color]

string, more likely (zip is a ZipFile object, picture is a string of
bytes). PIL expects a file name or a file object, so you need to use
the StringIO adapter:

picture = zip.read(name) # returns a string
file = StringIO.String IO(picture) # wrap string in file-like object
image = Image.open(file ) # create image object from file-like object

</F>

[Fredrik Lundh]

Re: Simple script to make .png thumbnails from .zip archive...

K P S wrote:
[color=blue]
> What I want is a little more involved, I guess, since I
> don't know the name of the file (for the zip.read command)[/color]

the first example on this page shows you how to get the names of all
files in a zip file:

http://effbot.org/librarybook/zipfile.htm

</F>

[K P S]

Re: Simple script to make .png thumbnails from .zip archive...

Thanks everyone.

One last thing (I hope).

How can I get the name of just the first file in a zipfile? I see
routines to list all the files in a zip archive, but I don't see any to
list only the first, or only the second, etc. It doesn't look like
zipfile is storing info in a useful array that I can hash into. Or is
it?

Actually, I would like to get the name of the first file with a .jpg
extension, if that's not asking too much. :-)

zip=zipfile.Zip File("text.zip" ,mode="r")
picture=zip.rea d(zip.namelist( 0))

This doesn't seem to work. :-(

[hdante@gmail.com]

Re: Simple script to make .png thumbnails from .zip archive...

K P S wrote:[color=blue]
> Thanks everyone.[/color]
[color=blue]
> routines to list all the files in a zip archive, but I don't see any to
> list only the first, or only the second, etc. It doesn't look like[/color]

If you can list all the files, then you can list only the first. :-)
Don't worry about python internal allocation procedures. It will try to
make things in an efficient way. Just make sure your code looks cool.
;-)
[color=blue]
>
> zip=zipfile.Zip File("text.zip" ,mode="r")
> picture=zip.rea d(zip.namelist( 0))[/color]

That's because you're using the wrong syntax. -> zip.namelist()[0]

However, I bet that your first file in the zip is not a jpeg file. Do
this, instead:

zip = zipfile.ZipFile ('text.zip')
jpeglist = [x for x in zip.namelist() if '.jp' in x]
try:
picture = zip.read(jpegli st[0])
except IndexError:
print 'No jpeg found'

[K P S]

Re: Simple script to make .png thumbnails from .zip archive...

Thanks a lot! This is what I ended up with.
(I would like to get rar archive support, but browsing the web it looks
like rar support isn't in any python library (yet)) :-( Anyway, I was
able to use the below code unchanged to create thumbnails in nautilus
based on the first .jpg file in a .zip archive.

Is there any rar support module in python?

Thanks again.


#!/usr/bin/python

import zipfile
import sys
import gnomevfs
import Image
import StringIO

inURL=gnomevfs. get_local_path_ from_uri(sys.ar gv[1])
outURL=sys.argv[2]

zip=zipfile.Zip File(inURL,mode ="r")
jpeglist=[x for x in zip.namelist() if '.jp' in x]
try:
picture=zip.rea d(jpeglist[0])
except IndexError:
print 'No jpeg found'

zip.close() #close the file, since we no longer have need of it
image = Image.open(Stri ngIO.StringIO(p icture)) # create image object
from file-like object
image.thumbnail ((128,128),Imag e.ANTIALIAS) #create the thumbnail
image.save (outURL, "PNG") #output the file in the proper format