Can Python format long integer 123456789 to 12,3456,789 ?

[A.M]

Hi,

Is there any built in feature in Python that can format long integer
123456789 to 12,3456,789 ?

Thank you,
Alan

[John Machin]

Re: Can Python format long integer 123456789 to 12,3456,789 ?

On 2/06/2006 9:08 AM, A.M wrote:[color=blue]
> Hi,
>
> Is there any built in feature in Python that can format long integer
> 123456789 to 12,3456,789 ?
>
> Thank you,
> Alan[/color]

Not that I know of, but this little kludge may help:
8<---
import re

subber = re.compile(r'^(-?\d+)(\d{3})'). sub

def fmt_thousands(a mt, sep):
if amt in ('', '-'):
return ''
repl = r'\1' + sep + r'\2'
while True:
new_amt = subber(repl, amt)
if new_amt == amt:
return amt
amt = new_amt

if __name__ == "__main__":
for prefix in ['', '-']:
for k in range(11):
arg = prefix + "1234567890.123 4"[k:]
print "<%s> <%s>" % (arg, fmt_thousands(a rg, ","))
8<---

HTH,
John

[John Machin]

Re: Can Python format long integer 123456789 to 12,3456,789 ?


A.M wrote:[color=blue]
> Hi,
>
> Is there any built in feature in Python that can format long integer
> 123456789 to 12,3456,789 ?
>[/color]

Sorry about my previous post. It would produce 123,456,789.
"12,3456,78 9" is weird -- whose idea PHB or yours??

[Ben Cartwright]

Re: Can Python format long integer 123456789 to 12,3456,789 ?

A.M wrote:[color=blue]
> Is there any built in feature in Python that can format long integer
> 123456789 to 12,3456,789 ?[/color]

The locale module can help you here:
[color=blue][color=green][color=darkred]
>>> import locale
>>> locale.setlocal e(locale.LC_ALL , '')[/color][/color][/color]
'English_United States.1252'[color=blue][color=green][color=darkred]
>>> locale.format(' %d', 123456789, True)[/color][/color][/color]
'123,456,789'

Be sure to read the caveats for setlocale in the module docs:

http://docs.python.org/lib/node323.html

I'd recommend calling setlocale only once, and always at the start of
your program.

--Ben

[james.wondrasek@gmail.com]

Re: Can Python format long integer 123456789 to 12,3456,789 ?


A.M wrote:[color=blue]
> Hi,
>
> Is there any built in feature in Python that can format long integer
> 123456789 to 12,3456,789 ?
>
> Thank you,
> Alan[/color]

I did this for putting commas into monetary amounts (thus the .2f):

def commas(value):
return "".join(commafy ("%.2f" % value))

def commafy(s):
pieces = s.split(".")
l = len(pieces[0])
for i in range(0,l):
if (l - i) % 3 or not i:
yield pieces[0][i]
else:
yield ","
yield pieces[0][i]
if len(pieces) > 1:
yield "." + pieces[1]


jtm

[Ben Cartwright]

Re: Can Python format long integer 123456789 to 12,3456,789 ?

John Machin wrote:[color=blue]
> A.M wrote:[color=green]
> > Hi,
> >
> > Is there any built in feature in Python that can format long integer
> > 123456789 to 12,3456,789 ?
> >[/color]
>
> Sorry about my previous post. It would produce 123,456,789.
> "12,3456,78 9" is weird -- whose idea PHB or yours??[/color]

If it's not a typo, it's probably a regional thing. See, e.g.,

http://en.wikipedia.org/wiki/Indian_numbering_system

--Ben

[John Machin]

Re: Can Python format long integer 123456789 to 12,3456,789 ?


james.wondrasek @gmail.com wrote:[color=blue]
> A.M wrote:[color=green]
> > Hi,
> >
> > Is there any built in feature in Python that can format long integer
> > 123456789 to 12,3456,789 ?
> >
> > Thank you,
> > Alan[/color]
>
> I did this for putting commas into monetary amounts (thus the .2f):
>
> def commas(value):
> return "".join(commafy ("%.2f" % value))
>
> def commafy(s):
> pieces = s.split(".")
> l = len(pieces[0])
> for i in range(0,l):
> if (l - i) % 3 or not i:
> yield pieces[0][i]
> else:
> yield ","
> yield pieces[0][i]
> if len(pieces) > 1:
> yield "." + pieces[1]
>[/color]

I dips me lid -- that's far fuglier than mine!!!

[A.M]

Re: Can Python format long integer 123456789 to 12,3456,789 ?



Thanks for help. Is there any comprehensive library for number formatting
available on the net?



Alan

[D H]

Re: Can Python format long integer 123456789 to 12,3456,789 ?

A.M wrote:[color=blue]
> Hi,
>
> Is there any built in feature in Python that can format long integer
> 123456789 to 12,3456,789 ?[/color]

Apparently you need to use the locale module. This is the
example they give online to print a simple number with commas:

import locale
locale.setlocal e(locale.LC_ALL , 'English_United States.1252')
print locale.format(" %d", 123456789, grouping=True)

Someone should make a module that uses .NET or Java's formmating.
You just use {0:n} or ###,### instead of all the above.

http://blog.stevex.net/index.php/string-formatting-in-csharp/

http://java.sun.com/docs/books/tutor...malFormat.html

[Warren Block]

Re: Can Python format long integer 123456789 to 12,3456,789 ?

John Machin <sjmachin@lexic on.net> wrote:[color=blue]
> On 2/06/2006 9:08 AM, A.M wrote:[color=green]
>> Hi,
>>
>> Is there any built in feature in Python that can format long integer
>> 123456789 to 12,3456,789 ?
>>
>> Thank you,
>> Alan[/color]
>
> Not that I know of, but this little kludge may help:
> 8<---
> import re
>
> subber = re.compile(r'^(-?\d+)(\d{3})'). sub
>
> def fmt_thousands(a mt, sep):
> if amt in ('', '-'):
> return ''
> repl = r'\1' + sep + r'\2'
> while True:
> new_amt = subber(repl, amt)
> if new_amt == amt:
> return amt
> amt = new_amt
>
> if __name__ == "__main__":
> for prefix in ['', '-']:
> for k in range(11):
> arg = prefix + "1234567890.123 4"[k:]
> print "<%s> <%s>" % (arg, fmt_thousands(a rg, ","))
> 8<---[/color]

Why not just port the Perl "commify" code? You're close to it, at least
for the regex:

# From perldoc perlfaq5
# 1 while s/^([-+]?\d+)(\d{3})/$1,$2/;

# Python version

import re

def commify(n):
while True:
(n, count) = re.subn(r'^([-+]?\d+)(\d{3})', r'\1,\2', n)
if count == 0: break
return n

--
Warren Block * Rapid City, South Dakota * USA