unzip zip files

Collapse
This topic is closed.
X
X
Collapse
 
  • Page of 1
  • Time
  • Show
Clear All
new posts
Previous template Next
  • DataSmash
    #1

    unzip zip files

    I need to unzip all zip file(s) in the current directory
    into their own subdirectories. The zip file name(s) always
    start with the string "usa" and end with ".zip".
    The code below will make the subdirectory, move the zip
    file into the subdirectory, but unzips the contents into the
    root (current) directory. I want the contents of the zip file
    unloaded into the newly created subdirectory where the zip file is.

    Any ideas?
    Thanks.
    R.D.

    import subprocess

    # Get all the zip files in the current directory.
    for zip in os.listdir(''):
    if zip.endswith(". zip"):

    # Remove the first 3 and the last 4 characters
    # e.g. usa12345.zip becomes 12345
    zipBase = zip[3:-4]

    # Make directory for unzipping
    os.mkdir(zipBas e)

    # Move the zip file to the subdirectory
    shutil.move(zip , zipBase)

    # Make system call "unzip"
    subprocess.Pope n(["unzip", zipBase + "\\" + zip]).wait()

    Tags: None
    • Marcelo Ramos
      #2
      Re: unzip zip files

      DataSmash escribió:[color=blue]
      > I need to unzip all zip file(s) in the current directory
      > into their own subdirectories. The zip file name(s) always
      > start with the string "usa" and end with ".zip".
      > The code below will make the subdirectory, move the zip
      > file into the subdirectory, but unzips the contents into the
      > root (current) directory. I want the contents of the zip file
      > unloaded into the newly created subdirectory where the zip file is.
      >
      > Any ideas?
      > Thanks.
      > R.D.
      >
      > import subprocess
      >
      > # Get all the zip files in the current directory.
      > for zip in os.listdir(''):
      > if zip.endswith(". zip"):
      >
      > # Remove the first 3 and the last 4 characters
      > # e.g. usa12345.zip becomes 12345
      > zipBase = zip[3:-4]
      >
      > # Make directory for unzipping
      > os.mkdir(zipBas e)
      >
      > # Move the zip file to the subdirectory
      > shutil.move(zip , zipBase)
      >
      > # Make system call "unzip"
      > subprocess.Pope n(["unzip", zipBase + "\\" + zip]).wait()
      >
      >[/color]

      See "-d" zip's parameter in man zip.

      Regards.

      --
      Marcelo Ramos
      Fedora Core 5 | 2.6.16
      Socio UYLUG Nro 125

        Comment

        • Edward Elliott
          #3
          Re: unzip zip files

          Marcelo Ramos wrote:
          [color=blue]
          > DataSmash escribió:[color=green]
          >> file into the subdirectory, but unzips the contents into the
          >> root (current) directory. I want the contents of the zip file
          >> unloaded into the newly created subdirectory where the zip file is.
          >>[/color]
          >
          > See "-d" zip's parameter in man zip.[/color]

          or change the working dir before calling unzip.

          --
          Edward Elliott
          UC Berkeley School of Law (Boalt Hall)
          complangpython at eddeye dot net

            Comment

            • Jay Parlar
              #4
              Re: unzip zip files


              On May 12, 2006, at 5:45 PM, DataSmash wrote:
              [color=blue]
              > I need to unzip all zip file(s) in the current directory
              > into their own subdirectories. The zip file name(s) always
              > start with the string "usa" and end with ".zip".
              > The code below will make the subdirectory, move the zip
              > file into the subdirectory, but unzips the contents into the
              > root (current) directory. I want the contents of the zip file
              > unloaded into the newly created subdirectory where the zip file is.
              >
              > Any ideas?
              > Thanks.
              > R.D.
              >
              > import subprocess
              >
              > # Get all the zip files in the current directory.
              > for zip in os.listdir(''):
              > if zip.endswith(". zip"):
              >
              > # Remove the first 3 and the last 4 characters
              > # e.g. usa12345.zip becomes 12345
              > zipBase = zip[3:-4]
              >
              > # Make directory for unzipping
              > os.mkdir(zipBas e)
              >
              > # Move the zip file to the subdirectory
              > shutil.move(zip , zipBase)
              >
              > # Make system call "unzip"
              > subprocess.Pope n(["unzip", zipBase + "\\" + zip]).wait()
              >[/color]


              Ouch... Is there any reason that you're using subprocess+'unz ip', as
              opposed to using the 'zipfile' module from the standard library?

              Jay P.

                Comment

                • DataSmash
                  #5
                  Re: unzip zip files

                  Thanks!
                  I ended up using the "-d" parameter.
                  I did try the zipfile module but I couldn't figure it out, nor could I
                  find any examples using it.
                  I also didn't have any luck changing the working dircectory and making
                  it work.

                  import subprocess, os

                  # Get all the zip files in the current directory.
                  for zip in os.listdir(''):
                  if zip.endswith(". zip"):

                  # Remove the first 3 and the last 4 characters
                  # e.g. usa12345.zip becomes 12345
                  zipBase = zip[3:-4]

                  # Make directory for unzipping
                  os.mkdir(zipBas e)

                  # Make system call "unzip"
                  print "\n unzip -d", zipBase, zip
                  subprocess.Pope n(["unzip", "-d", zipBase, zip]).wait()

                    Comment

                    Previous template Next
                    Working...