stripping

[micklee74@hotmail.com]

hi
i have a file test.dat eg

abcdefgh
ijklmn
<-----newline
opqrs
tuvwxyz
<---newline


I wish to print the contents of the file such that it appears:
abcdefgh
ijklmn
opqrs
tuvwxyz

here is what i did:
f = open("test.dat" )
while 1:
line = f.readline().rs trip("\n")
if line == '':
break
#if not re.findall(r'^$ ',line):
print line

but it always give me first 2 lines, ie
abcdefgh
ijklmn

What can i do to make it print all..?
thanks

[Edward Elliott]

Re: stripping

micklee74@hotma il.com wrote:[color=blue]
> while 1:
> line = f.readline().rs trip("\n")
> if line == '':
> break
> #if not re.findall(r'^$ ',line):
> print line[/color]

you want continue, not break there. but that gives you an infinite loop, so
you need a new exit condition. you're better off scrapping the while and
using a for loop or list comprehension on readline.

[Jesse Hager]

Re: stripping

micklee74@hotma il.com wrote:[color=blue]
> hi
> i have a file test.dat eg
>
> abcdefgh
> ijklmn
> <-----newline
> opqrs
> tuvwxyz
> <---newline
>
>
> I wish to print the contents of the file such that it appears:
> abcdefgh
> ijklmn
> opqrs
> tuvwxyz
>
> here is what i did:
> f = open("test.dat" )
> while 1:
> line = f.readline().rs trip("\n")
> if line == '':
> break
> #if not re.findall(r'^$ ',line):
> print line
>
> but it always give me first 2 lines, ie
> abcdefgh
> ijklmn
>
> What can i do to make it print all..?
> thanks
>[/color]
Change the 'break' statement to a 'continue'.

--
Jesse Hager
email = "wrffruntre@tzn vy.pbz".decode( "rot13")