a question on re

[eight02645999@yahoo.com]

hi

i tried to search 2 patterns

pat1 = re.compile("bla h")
pat2 = re.compile("bla h2")


if i do
if re.findall(pat1 ,something) and re.findall(pat2 ,something):
do something

if does not work

but when i do a nest if,

if re.findall(pat1 ,something) :
if re.findall(pat2 ,something):
do something

it works..

please advise on why the first code doesnt work.
thanks

[Marco Wahl]

Re: a question on re

Hi,
[color=blue]
> i tried to search 2 patterns
>
> pat1 = re.compile("bla h")
> pat2 = re.compile("bla h2")
>
>
> if i do
> if re.findall(pat1 ,something) and re.findall(pat2 ,something):
> do something
>
> if does not work
>
> but when i do a nest if,
>
> if re.findall(pat1 ,something) :
> if re.findall(pat2 ,something):
> do something
>
> it works..
>
> please advise on why the first code doesnt work.[/color]

it's not perfectly clear to me what you mean with 'doesnt work'.

The two if parts
[color=blue]
> if re.findall(pat1 ,something) and re.findall(pat2 ,something):
> do something[/color]

and
[color=blue]
> if re.findall(pat1 ,something) :
> if re.findall(pat2 ,something):
> do something[/color]

look equivalent to me. Could you please reveal your
value for text-string 'something'? Further I suggest
to replace the 'do something'-parts with 'print 42'.


Best wishes Marco

[Fredrik Lundh]

Re: a question on re

eight02645999@y ahoo.com wrote
[color=blue]
> i tried to search 2 patterns
>
> pat1 = re.compile("bla h")
> pat2 = re.compile("bla h2")
>
>
> if i do
> if re.findall(pat1 ,something) and re.findall(pat2 ,something):
> do something
>
> if does not work
>
> but when i do a nest if,
>
> if re.findall(pat1 ,something) :
> if re.findall(pat2 ,something):
> do something
>
> it works..
>
> please advise on why the first code doesnt work.[/color]

is this the actual code you were using ? and the actual patterns ?
what's in "something" ?

</F>