how to capture os.execvp into variable

[s99999999s2003@yahoo.com]

hi
i am using this code to run a ps command in unix

def run(program, *args):
pid = os.fork()
if not pid:
os.execvp(progr am, (program,) + args)
return os.wait()[0]

run("ps", "-eo pid,ppid,args")

It runs fine, but i wish to store the results into a variable....how
can i do this ? I tried
to put ret=os.execvp(p rogram, (program,) + args) but ret has no value
thanks

[Ben C]

Re: how to capture os.execvp into variable

On 2006-03-28, s99999999s2003@ yahoo.com <s99999999s2003 @yahoo.com> wrote:[color=blue]
> hi
> i am using this code to run a ps command in unix
>
> def run(program, *args):
> pid = os.fork()
> if not pid:
> os.execvp(progr am, (program,) + args)
> return os.wait()[0]
>
> run("ps", "-eo pid,ppid,args")
>
> It runs fine, but i wish to store the results into a variable....how
> can i do this ? I tried
> to put ret=os.execvp(p rogram, (program,) + args) but ret has no value
> thanks[/color]

Do you mean you want the output of ps? That seems most likely. In that
case use os.popen.

p = os.popen("ps -eo pid,ppid,args")
output = p.read()
p.close()