by reference

[dirvine]

I would like to create a dictionary based on a variable i.e read a
bunch of filenames and create a dict for each one called the filename
filename={}
to get the filenames I trraverse teh dirs woth os.path.walk or similar

Sorry I'm a bit new to python

[Rene Pijlman]

Re: by reference

dirvine:[color=blue]
>I would like to create a dictionary based on a variable [...][/color]

And what seems to be the problem?

--
René Pijlman

[Martin P. Hellwig]

Re: by reference

Rene Pijlman wrote:[color=blue]
> dirvine:[color=green]
>> I would like to create a dictionary based on a variable [...][/color]
>
> And what seems to be the problem?
>[/color]
I think that this is his problem:
[color=blue][color=green][color=darkred]
>>> 'somename'={}[/color][/color][/color]
SyntaxError: can't assign to literal

But I'm puzzled why he wants that route, while I'm still pretty new to
programming, I usually smell a design fault when I want to try to
squeeze a literal name into a object variable (am I'm saying this
correct?). Most of the time nesting dictionaries will do the trick for me:
[color=blue][color=green][color=darkred]
>>> sharedDict=dict ()
>>> sharedDict['somename']=dict()
>>> sharedDict['someothername']=dict()
>>> sharedDict[/color][/color][/color]
{'somename': {}, 'someothername' : {}}[color=blue][color=green][color=darkred]
>>>[/color][/color][/color]

--
mph