urlretrieve() questions

[Rene Lopez]

I'm building an app that needs to download a file from the
web.

I'm trying to make sure I catch any issues with the download
but I've run into a problem.

here's what I have so far:

try:
urllib.urlretri eve(url,filenam e)
print "File: ", filename, " downloaded"
except IOError:
print "IOError File Not Found: ", url

Pretty straight forward...but what I'm finding is if the
url is pointing to a file that is not there, the server
returns a file that's a web page displaying a 404 error.

Anyone have any recommendations for handling this?
--

Rene

[Dan M]

Re: urlretrieve() questions

> Pretty straight forward...but what I'm finding is if the[color=blue]
> url is pointing to a file that is not there, the server
> returns a file that's a web page displaying a 404 error.
>
> Anyone have any recommendations for handling this?[/color]

You're right, that is NOT documented in a way that's easy to find!

What I was able to find is how to what you want using urllib2 instead of
urllib. I found an old message thread that touches on the topic:

http://groups.google.com/group/comp.lang.python/browse_thread/thread/3f02bee97a689927/88c7bfec87e18ba9?q=%22http+status%22+%2Burllib&rnum=3#88c7bfec87e18ba9

(also accessable as http://tinyurl.com/952dw). Here's a quick summary:
-----------------------------------------------------------------------

Ivan Karajas
Apr 28 2004, 11:03 pm show options
Newsgroups: comp.lang.pytho n
From: Ivan Karajas <my_full_name_c oncatena...@myr ealbox.com> - Find messages by this author
Date: Wed, 28 Apr 2004 23:03:54 -0800
Local: Wed, Apr 28 2004 11:03 pm
Subject: Re: 404 errors
Reply to Author | Forward | Print | Individual Message | Show original | Report Abuse

On Tue, 27 Apr 2004 10:46:47 +0200, Tut wrote:[color=blue]
> Tue, 27 Apr 2004 11:00:57 +0800, Derek Fountain wrote:[/color]
[color=blue][color=green]
>> Some servers respond with a nicely formatted bit of HTML explaining the
>> problem, which is fine for a human, but not for a script. Is there some
>> flag or something definitive on the response which says "this is a 404
>> error"?[/color][/color]
[color=blue]
> Maybe catch the urllib2.HTTPErr or?[/color]

This kind of answers the question. urllib will let you read whatever it
receives, regardless of the HTTP status; you need to use urllib2 if you
want to find out the status code when a request results in an error (any
HTTP status beginning with a 4 or 5). This can be done like so:

import urllib2
try:
asock = urllib2.urlopen ("http://www.foo.com/qwerty.html")
except urllib2.HTTPErr or, e:
print e.code

The value in urllib2.HTTPErr or.code comes from the first line of the web
server's HTTP response, just before the headers begin, e.g. "HTTP/1.1 200
OK", or "HTTP/1.1 404 Not Found".

One thing you need to be aware of is that some web sites don't behave as
you would expect them to; e.g. responding with a redirection rather than a
404 error when you when you request a page that doesn't exist. In these
cases you might still have to rely on some clever scripting.
----------------------------------------------------------------------

I hope that helps.

Dan