Problem with os.path

[Daya Kiran Sunkara]

Hi All,

I have a program which fetches the list of files inside a directory.
For fetching this list I am making use of the glob.glob method which
takes path as a parameter.
For building the path I am making use of os.path.join. My code looks
somewhat like this:
-----------------------------------------------------------------------
import glob
import os
path = 'E:\mktrisk\ser vice\marketdata \da'
for filename in glob.glob(os.pa th.join(path,'* .java')):
datafile = open(filename,' r').readlines()
----------------------------------------------------------------------

this program works fine when the string 'path' is not too long. When I
pass a longer string as path, the program doesn't work. Now I am not
sure whether its a limitation with the string class or with os.path. I
am passing a valid path to the program and I am running this on Python
2.4.2 on Windows XP.

Any help will be greatly appreciated.

regards,
Daya

[Pelmen]

Re: Problem with os.path

sorry? if i'm wrong? but i'm think you have to use double slash, to
prevent escape-interpreting as '\n' for example

[Scott David Daniels]

Re: Problem with os.path

Daya Kiran Sunkara wrote:[color=blue]
> ...
> path = 'E:\mktrisk\ser vice\marketdata \da'[/color]
You should use:
path = r'E:\mktrisk\se rvice\marketdat a\da'
if you want to use backslashes regularly (for regexps and paths).
You do know you could also use:
path = 'E:/mktrisk/service/marketdata/da'
even on windows.

--Scott David Daniels
scott.daniels@a cm.org