Using open() inside a subroutine

[imphasing]

Whenever I try to open a file inside a subroutine, like so:

def open():
filePath=askope nfilename()

fileOpen = open(filePath, "r")
fileContent = fileOpen.read()
fileOpen.close( )

it tells me that "open() takes no arguments (2 given)"
Why is that? and how can I get around that so I can open a file in a
subroutine?

Thanks,
Alex

[Grant Edwards]

Re: Using open() inside a subroutine

On 2005-02-18, imphasing <alex@fortworks .com> wrote:[color=blue]
> Whenever I try to open a file inside a subroutine, like so:
>
> def open():
> filePath=askope nfilename()
>
> fileOpen = open(filePath, "r")
> fileContent = fileOpen.read()
> fileOpen.close( )
>
> it tells me that "open() takes no arguments (2 given)"
> Why is that?[/color]

Because you defined open() as taking no arguments. You're
calling your own open() function, not the builtin one.
[color=blue]
> and how can I get around that so I can open a file in a
> subroutine?[/color]

Don't call your function open().

--
Grant Edwards grante Yow! Th' MIND is the Pizza
at Palace of th' SOUL
visi.com

[imphasing]

Re: Using open() inside a subroutine

DUH. Thanks.
can't beleive I missed that one...

Alex