File this one under "enhancemen t request" I guess, but it would sure be
nice. I wrote this line the other day, thinking it would just work:
x = struct.pack(">H hhhhhhHHHL", i, *bounds, *b[0:2], *b[6:9], len(s))
Unfortunately, it doesn't. The only valid place for an "*"-style
argument is at the end of the arguments list. But this line seems so
natural! Since struct.pack expects all its arguments separately (rather
than gathered into a list or tuple), I have to be able to accommodate
its needs, and since I had several arguments already in lists, I thought
I could get away with this notation.
Certainly I can get around this limitation by either spelling out the
arguments (i.e. b[0], b[1], b[6]...), or by writing multiple lines of
code to gather the arguments into a single list which could then have
the "*" applied. But I'd love a simpler, more compact notation, not
unlike what I've written above. Does anyone know of a current Python
idiom for unravelling list arguments in calls?
Dave
nice. I wrote this line the other day, thinking it would just work:
x = struct.pack(">H hhhhhhHHHL", i, *bounds, *b[0:2], *b[6:9], len(s))
Unfortunately, it doesn't. The only valid place for an "*"-style
argument is at the end of the arguments list. But this line seems so
natural! Since struct.pack expects all its arguments separately (rather
than gathered into a list or tuple), I have to be able to accommodate
its needs, and since I had several arguments already in lists, I thought
I could get away with this notation.
Certainly I can get around this limitation by either spelling out the
arguments (i.e. b[0], b[1], b[6]...), or by writing multiple lines of
code to gather the arguments into a single list which could then have
the "*" applied. But I'd love a simpler, more compact notation, not
unlike what I've written above. Does anyone know of a current Python
idiom for unravelling list arguments in calls?
Dave
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