__new__ to create copy

[Uwe Mayer]

Hi,

I want to create a copy of an object from out of its base class:

class A(object):
def copy(self):
....

class B(A):
....
[color=blue][color=green][color=darkred]
>>> b = B()
>>> b.copy()[/color][/color][/color]

I'm not sure how to do this:

def copy(self):
cpy = self.__new__(se lf.__class__)
return cpy

seems not to call the constructor __init__().

How is such a thing done correctly? Where is the exact difference between
__new__ and __init__?


Thanks
Uwe

[F. GEIGER]

Re: __new__ to create copy

I do object copies this way:

import copy

a = A()
aa = copy.copy(a)

or

aa = copy.deepcopy(a )

You can wrap this up into a method of course, which then can decide whether
to do a deep copy or not.

HTH
Franz GEIGER


"Uwe Mayer" <merkosh@hadiko .de> schrieb im Newsbeitrag
news:bvvprg$81b $1@news.rz.uni-karlsruhe.de...[color=blue]
> Hi,
>
> I want to create a copy of an object from out of its base class:
>
> class A(object):
> def copy(self):
> ...
>
> class B(A):
> ...
>[color=green][color=darkred]
> >>> b = B()
> >>> b.copy()[/color][/color]
>
> I'm not sure how to do this:
>
> def copy(self):
> cpy = self.__new__(se lf.__class__)
> return cpy
>
> seems not to call the constructor __init__().
>
> How is such a thing done correctly? Where is the exact difference between
> __new__ and __init__?
>
>
> Thanks
> Uwe[/color]

[Josiah Carlson]

Re: __new__ to create copy

> How is such a thing done correctly? Where is the exact difference between[color=blue]
> __new__ and __init__?[/color]

For some reason, I'm not finding the doc page, but I am pretty sure the
below is the case.
If __new__ exists, it will be called.
If __new__ exists, it must call __init__ for __init__ to be called.
If __new__ doesn't exist, __init__ will be called, if it exists.


How I usually copy my classes:

class blah:
def __init__(self, arg1, arg2, ...):
self.arg1 = arg1
self.arg2 = arg2
...
def copy(self):
return blah(self.arg1, self.arg2, ...)

It may not be pretty, but it works.

- Josiah