Simple way to get the full path of a running script?

[Benjamin Han]

I know I can do this by get sys.argv[0], tell if it's a full path, and if not,
somehow join the relative path with getcwd(). Just wondering if there's a
simpler way to do this. Thanks!

[Benjamin Han]

Re: Simple way to get the full path of a running script?

Duh - the way I described seems to be simple enough:

pathToScript=os .join(os.getcwd (),os.path.spli t(sys.argv[0])[0])


On Sat, 27 Dec 2003, Benjamin Han wrote:
[color=blue]
> I know I can do this by get sys.argv[0], tell if it's a full path, and if not,
> somehow join the relative path with getcwd(). Just wondering if there's a
> simpler way to do this. Thanks!
>[/color]

[Benjamin Han]

Re: Simple way to get the full path of a running script?

Should be:

pathToScript=\
os.path.normpat h(os.path.join( os.getcwd(),os. path.split(sys. argv[0])[0]))

On Sat, 27 Dec 2003, Benjamin Han wrote:
[color=blue]
> Duh - the way I described seems to be simple enough:
>
> pathToScript=os .join(os.getcwd (),os.path.spli t(sys.argv[0])[0])
>
>
> On Sat, 27 Dec 2003, Benjamin Han wrote:
>[color=green]
> > I know I can do this by get sys.argv[0], tell if it's a full path, and if not,
> > somehow join the relative path with getcwd(). Just wondering if there's a
> > simpler way to do this. Thanks!
> >[/color]
>[/color]

[Mark McEahern]

Re: Simple way to get the full path of a running script?

On Sat, 2003-12-27 at 18:02, Benjamin Han wrote:[color=blue]
> Duh - the way I described seems to be simple enough:
>
> pathToScript=os .join(os.getcwd (),os.path.spli t(sys.argv[0])[0])[/color]

Or:

#!/usr/bin/env python

import sys
import os

me = sys.argv[0]
print "This is how you invoked me: %s" % (me,)
print "This is the absolute path: %s" % (os.path.abspat h(me),)

Usage:

mark@dev /var/tmp/buffer
$ python ../junk.py
This is how you invoked me: ../junk.py
This is the absolute path: /var/tmp/junk.py

Cheers,

// m

[Benjamin Han]

Re: Simple way to get the full path of a running script?

On Sat, 27 Dec 2003, Mark McEahern wrote:
[color=blue]
> On Sat, 2003-12-27 at 18:02, Benjamin Han wrote:[color=green]
> > Duh - the way I described seems to be simple enough:
> >
> > pathToScript=os .join(os.getcwd (),os.path.spli t(sys.argv[0])[0])[/color]
>
> me = sys.argv[0]
> print "This is the absolute path: %s" % (os.path.abspat h(me),)[/color]

Thank you - this is even better!

[Lee Harr]

Re: Simple way to get the full path of a running script?

> #!/usr/bin/env python[color=blue]
>
> import sys
> import os
>
> me = sys.argv[0]
> print "This is how you invoked me: %s" % (me,)
> print "This is the absolute path: %s" % (os.path.abspat h(me),)
>
> Usage:
>
> mark@dev /var/tmp/buffer
> $ python ../junk.py
> This is how you invoked me: ../junk.py
> This is the absolute path: /var/tmp/junk.py
>[/color]


Is this going to work well cross platform? How about from IDLE?

I was using sys.path[0] which I thought was working well, but
apparently fails when the script is run from IDLE on windows.

[Wolfgang Lipp]

Re: Simple way to get the full path of a running script?

i normally use the following:

import inspect
print inspect.getsour cefile( lambda:None )

the lambda function could be any object; the getsourcefile returns the
path to the file where that object was defined.

_wolf

[Hartmut Goebel]

Re: Simple way to get the full path of a running script?

Hi,

Wolfgang Lipp schrieb:
[color=blue]
> import inspect
> print inspect.getsour cefile( lambda:None )[/color]

Nice idea!

Enhancement: when using inspect.getfile () the snippet will work even for
module without sourcefile, too.

--
Regards
Hartmut Goebel

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