searching structures

[Alberto Vera]

Hello:

I have next structures:

A[1,2,3]
AB[4,5,6]
ABC[7,8,9]
ABCD[1,2,3]
ABCDE[4,5,6]
ABCDEF[7,8,9]

I'd like to know how many 'arrays' start with ABCD like ABCD*
(ABCD,ABCDE,ABC DEF)

Is it possible to do it using Python?

Regards

[Alan Kennedy]

Re: searching structures

[Alberto Vera][color=blue]
> I have next structures:
>
> A[1,2,3]
> AB[4,5,6]
> ABC[7,8,9]
> ABCD[1,2,3]
> ABCDE[4,5,6]
> ABCDEF[7,8,9]
> I'd like to know how many 'arrays' start with ABCD like ABCD*
> (ABCD,ABCDE,ABC DEF)
>
> Is it possible to do it using Python?[/color]

That depends on how they are stored. Are they stored in some form of
data structure? Or in a file?

More details required.

--
alan kennedy
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[Dave Kuhlman]

Re: searching structures

Alberto Vera wrote:
[color=blue]
> Hello:
>
> I have next structures:
>
> A[1,2,3]
> AB[4,5,6]
> ABC[7,8,9]
> ABCD[1,2,3]
> ABCDE[4,5,6]
> ABCDEF[7,8,9]
>
> I'd like to know how many 'arrays' start with ABCD like ABCD*
> (ABCD,ABCDE,ABC DEF)
>
> Is it possible to do it using Python?[/color]

Sounds like you want to filter on the *name* of the the array. If
so, think about doing something like the following:
[color=blue][color=green][color=darkred]
>>> aa = 1
>>> aab = 2
>>> bb = 3
>>>
>>> dir()[/color][/color][/color]
['__builtins__', '__doc__', '__file__', '__name__', 'aa', 'aab',
'bb'][color=blue][color=green][color=darkred]
>>> for x in dir():[/color][/color][/color]
... if x[:2] == 'aa':
... print 'yes', x
... else:
... print 'no', x
...
no __builtins__
no __doc__
no __file__
no __name__
yes aa
yes aab
no bb

And if you need to distinguish the *type* of the value of the
variable, consider using type().

The built-in functions globals() and locals() give dictionaries
that contain variable name-value pairs.

These built-in functions are described at:

http://www.python.org/doc/current/lib/built-in-funcs.html

Dave


--
Dave Kuhlman

http://www.rexx.com/~dkuhlman

dkuhlman@rexx.c om