raw string

[Marc Petitmermet]

I can do the following replacement:

r"kr\xdf6;ger". replace('\\','& #')
-> 'kr෶ger'

But how can I do this using a variable which contains the above string?
Obviously, the following code returns not the string with replacement
but the name of the variable itself:

name = "kr\xdf6;ge r"
r"name".replace ('\\','&#')
-> 'r"name"

Sorry, if this is a stupid question but I have not found an answer so
far (or I have been using the wrong keywords for searching).

Thanks for any help.
Regards,
Marc

[David C. Fox]

Re: raw string

Marc Petitmermet wrote:[color=blue]
> I can do the following replacement:
>
> r"kr\xdf6;ger". replace('\\','& #')
> -> 'kr෶ger'
>
> But how can I do this using a variable which contains the above string?
> Obviously, the following code returns not the string with replacement
> but the name of the variable itself:
>
> name = "kr\xdf6;ge r"
> r"name".replace ('\\','&#')
> -> 'r"name"[/color]

name = r"kr\xdf6;ge r"
name.replace('\ \', '&#')

If you say name = "kr\xdf6;ge r" without the r prefix, the \x has already
been replaced with a single character, and there is no slash in the
string, so it is too late to try to replace a slash with something else.

David

[Patrick Useldinger]

Re: raw string

On Sat, 20 Sep 2003 21:10:46 +0200, Marc Petitmermet
<petitmermet@ma t.ethz.ch> wrote:
[color=blue]
>I can do the following replacement:
>
>r"kr\xdf6;ger" .replace('\\',' &#')
>-> 'kr&#xdf6;ger'
>
>But how can I do this using a variable which contains the above string?
>Obviously, the following code returns not the string with replacement
>but the name of the variable itself:
>
>name = "kr\xdf6;ge r"
>r"name".replac e('\\','&#')
>-> 'r"name"[/color]

name = r"kr\xdf6;ge r" (the r goes here)
name.replace('\ \','&#') (the name of the object must not be in quotes)

-PU