A strange behavior of list.extend()

[sdhyok]

I think the two script should produce the same results, but not.
Why?

---------------- Script #1
ls = [1]
ls.extend([2,3])
print ls
-> [1,2,3]

--------------- Script #2
ls = [1].extend([2,3])
print ls
-> None

Daehyok

[mackstann]

Re: A strange behavior of list.extend()

On Sun, Aug 24, 2003 at 02:11:15PM -0700, sdhyok wrote:[color=blue]
> I think the two script should produce the same results, but not.
> Why?
>
> ---------------- Script #1
> ls = [1]
> ls.extend([2,3])
> print ls
> -> [1,2,3]
>
> --------------- Script #2
> ls = [1].extend([2,3])
> print ls
> -> None[/color]

list.extend happens in place and returns None, so your ls variable is
just getting the returned None. Same thing happens with sort:
[color=blue][color=green][color=darkred]
>>> [4,2,3,1].sort()
>>>[/color][/color][/color]

or:
[color=blue][color=green][color=darkred]
>>> f = [4,2,3,1]
>>> f.sort()
>>> f[/color][/color][/color]
[1, 2, 3, 4]


--
m a c k s t a n n mack @ incise.org http://incise.org
Excellent time to become a missing person.

[sdhyok]

Re: A strange behavior of list.extend()

Thanks. I got it.

Deahyok