data conversion question (binary string to 'real string')

[Alexander Eisenhuth]

Hallo all there,

maby I don't see the forest because of all that trees, but :

from struct import *


# how can I convert
f = float(0.5)

# with
bin_str = pack('!f', 0.5)

# now bin_str is '?\x00\x00\x00'


# to "3F000000" ?????


Thanks a lot for any help

[Alexander Eisenhuth]

Re: data conversion question (binary string to 'real string')

Manish Jethani wrote:[color=blue]
> Alexander Eisenhuth wrote:
>
>[color=green]
>>maby I don't see the forest because of all that trees, but :[/color]
>
>
> Maybe I don't understand your question...
>
>[color=green]
>>from struct import *
>>
>>
>># how can I convert
>>f = float(0.5)
>>
>># with
>>bin_str = pack('!f', 0.5)
>>
>># now bin_str is '?\x00\x00\x00'
>>
>>
>># to "3F000000" ?????[/color]
>
>
> ???????????????
> What is your question?
>
> -Manish
>[/color]
Sorry ...

This two lines converts 0.5 to a string in binary
representation
[color=blue][color=green][color=darkred]
>>>from struct import *
>>>bin_str = pack('!f', 0.5)[/color][/color][/color]

now bin_str is '?\x00\x00\x00' , wich is the representation
of 0.5 in the memory. I need now to convert this binary
string to "3F000000", where '3F' is the hex value of the '?'
in ascii - table.

Any ideas ??

Thaks
Alexander

[Alexander Eisenhuth]

Re: data conversion question (binary string to 'real string')

Manish Jethani wrote:[color=blue]
> Alexander Eisenhuth wrote:
>
>[color=green]
>>maby I don't see the forest because of all that trees, but :[/color]
>
>
> Maybe I don't understand your question...
>
>[color=green]
>>from struct import *
>>
>>
>># how can I convert
>>f = float(0.5)
>>
>># with
>>bin_str = pack('!f', 0.5)
>>
>># now bin_str is '?\x00\x00\x00'
>>
>>
>># to "3F000000" ?????[/color]
>
>
> ???????????????
> What is your question?
>
> -Manish
>[/color]
Sorry ...

This two lines converts 0.5 to a string in binary
representation
[color=blue][color=green][color=darkred]
>>>from struct import *
>>>bin_str = pack('!f', 0.5)[/color][/color][/color]

now bin_str is '?\x00\x00\x00' , wich is the representation
of 0.5 in the memory. I need now to convert this binary
string to "3F000000", where '3F' is the hex value of the '?'
in ascii - table.

Any ideas ??

Thaks
Alexander

[Manish Jethani]

Re: data conversion question (binary string to 'real string')

Alexander Eisenhuth wrote:
[color=blue]
> This two lines converts 0.5 to a string in binary
> representation
>[color=green][color=darkred]
> >>>from struct import *[/color][/color][/color]

from binascii import hexlify
[color=blue][color=green][color=darkred]
> >>>bin_str = pack('!f', 0.5)[/color][/color]
>
> now bin_str is '?\x00\x00\x00' , wich is the representation
> of 0.5 in the memory. I need now to convert this binary
> string to "3F000000", where '3F' is the hex value of the '?'
> in ascii - table.
>
> Any ideas ??[/color]

foo = hexlify(bin_str )
print foo

-Manish

PS: You posted the same message thrice, by mistake.

--
Manish Jethani (manish.j at gmx.net)
phone (work) +91-80-51073488

[Bengt Richter]

Re: data conversion question (binary string to 'real string')

On Fri, 25 Jul 2003 14:57:57 +0200, Alexander Eisenhuth <stacom@staco m-software.de> wrote:
[color=blue]
>Hallo all there,
>
>maby I don't see the forest because of all that trees, but :
>
>from struct import *
>
>
># how can I convert
>f = float(0.5)
>
># with
>bin_str = pack('!f', 0.5)
>
># now bin_str is '?\x00\x00\x00'
>
>
># to "3F000000" ?????
>
>[/color]
That leading '?' is the character representation of a string byte whose ordinal value
is 3F hex, followed by three characters represented by \x00 (whose ordinal
values are zero). I.e., your binary bytes are being represented as characters in a string,
and when it's shown interactively you see the values as a sequence of character glyphs
(or \x.. hex escape representations if no glyphs are available), which is the normal way
to display a string.

If you want the *hex string* representation of that string-represented byte sequence, you can
convert each byte-as-character first to its ordinal value and then the ordinal value to a
2-char hex string representation, and then join those all into a single string,
e.g.,, showing the character transformations :
[color=blue][color=green][color=darkred]
>>> [c for c in struct.pack('!f ', 0.5)][/color][/color][/color]
['?', '\x00', '\x00', '\x00'][color=blue][color=green][color=darkred]
>>> [ord(c) for c in struct.pack('!f ', 0.5)][/color][/color][/color]
[63, 0, 0, 0][color=blue][color=green][color=darkred]
>>> ['%02X'%ord(c) for c in struct.pack('!f ', 0.5)][/color][/color][/color]
['3F', '00', '00', '00']

And finally, all you need is
[color=blue][color=green][color=darkred]
>>> ''.join(['%02X'%ord(c) for c in struct.pack('!f ', 0.5)])[/color][/color][/color]
'3F000000'

Now you have a hex string representation of the network-ordered (big-endian-ordered)
bytes of a single precision (32-bit) float.

Regards,
Bengt Richter

[Bob Gailer]

Re: data conversion question (binary string to 'real string')

FWIW here's an interesting way to get at the bit:
if 13 is the number you want to represent in binary and you want 6 bits:[color=blue][color=green][color=darkred]
>>> [13>>x & 1 for x in range(6,-1,-1)][/color][/color][/color]
[0, 0, 0, 1, 1, 0, 1]

Bob Gailer
bgailer@alum.rp i.edu
303 442 2625


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