using extended built-in types

[Rim]

Hi,

When I extend a built-in type, how do I cause the extended type to
be used by default, without having to specify it? For instance, say I
extend the int type:

class myint(int):
def foo(self): print 'foo'

How do I make all future integers use myint instead of int without explicitely
say a = myint(value)?

Thanks
- Rim

[Martin v. Löwis]

Re: using extended built-in types

rimbalaya@yahoo .com (Rim) writes:
[color=blue]
> How do I make all future integers use myint instead of int without
> explicitely say a = myint(value)?[/color]

That is not possible.

Martin

[Andrew Bennetts]

Re: using extended built-in types

On Mon, Jun 30, 2003 at 05:40:06AM +0200, Martin v. L?wis wrote:[color=blue]
> rimbalaya@yahoo .com (Rim) writes:
>[color=green]
> > How do I make all future integers use myint instead of int without
> > explicitely say a = myint(value)?[/color]
>
> That is not possible.[/color]

If only ;)

If your tolerance for evil is sufficiently high, you could use intrinisics,
a hack by Jp Calderone...

PyCon lightning talk:

http://www.intarweb.us:8080/PyCon/intrinsics-lightning-0.xhtml

Source:

http://www.intarweb.us:8080/evil/intrinsics.c

-Andrew.

[Rim]

Re: using extended built-in types

> If only ;)[color=blue]
>
> If your tolerance for evil is sufficiently high, you could use intrinisics,
> a hack by Jp Calderone...
>
> PyCon lightning talk:
> http://www.intarweb.us:8080/PyCon/in...htning-0.xhtml
>
> Source:
> http://www.intarweb.us:8080/evil/intrinsics.c[/color]

The links do not work.

Thanks,
-Rim