shared library search path

[Stefan Arentz]

Hi. I've wrapped a C++ class with Boost.Python and that works great. But, I
am now packaging my application so that it can be distributed. The structure
is basically this:

.../bin/foo.py
.../lib/foo.so
.../lib/bar.py

In foo.py I do the following:

sys.path.append (os.path.dirnam e(sys.path[0]) + '/lib')

and this allows foo.py to import bar. Great.

But, the foo.so cannot be imported. The import only succeeds if I place
foo.so next to foo.py in the bin directory.

I searched through the 2.4.2 documentation on python.org but I can't find
a proper explanation on how the shared library loader works.

Does anyone understand what it going on here?

S.

[Neal Becker]

Re: shared library search path

Stefan Arentz wrote:
[color=blue]
>
> Hi. I've wrapped a C++ class with Boost.Python and that works great. But,
> I am now packaging my application so that it can be distributed. The
> structure is basically this:
>
> .../bin/foo.py
> .../lib/foo.so
> .../lib/bar.py
>
> In foo.py I do the following:
>
> sys.path.append (os.path.dirnam e(sys.path[0]) + '/lib')
>
> and this allows foo.py to import bar. Great.
>
> But, the foo.so cannot be imported. The import only succeeds if I place
> foo.so next to foo.py in the bin directory.
>
> I searched through the 2.4.2 documentation on python.org but I can't find
> a proper explanation on how the shared library loader works.
>
> Does anyone understand what it going on here?
>
> S.
>[/color]

No, but here is the code I use:
import sys
sys.path.append ('../wrap')