Lambda evaluation

[Joshua Ginsberg]

So this part makes total sense to me:
[color=blue][color=green][color=darkred]
>>> d = {}
>>> for x in [1,2,3]:[/color][/color][/color]
.... d[x] = lambda y: y*x
....[color=blue][color=green][color=darkred]
>>> d[1](3)[/color][/color][/color]
9

Because x in the lambda definition isn't evaluated until the lambda is
executed, at which point x is 3.

Is there a way to specifically hard code into that lambda definition the
contemporary value of an external variable? In other words, is there a
way to rewrite the line "d[x] = lambda y: y*x" so that it is always the
case that d[1](3) = 3?

Thanks!

-jag

[Steve M]

Re: Lambda evaluation

Here's another one:
[color=blue][color=green][color=darkred]
>>> d = {}
>>> for x in [1,2,3]:[/color][/color][/color]
.... d[x] = (lambda z: lambda y: y * z) (x)
....[color=blue][color=green][color=darkred]
>>> d[1](3)[/color][/color][/color]
3[color=blue][color=green][color=darkred]
>>> d[2](3)[/color][/color][/color]
6