Quick help needed: how to format an integer ?

[durumdara@mailpont.hu]

Hi !

I need to convert some integer values.

"1622" ->"1 622"

or

"10001234" -> ""10.001.23 4""

So I need thousand separators.

Can anyone helps me with a simply solution (like %xxx) ?

Thanx for it: dd

Ps:
Now I use this proc:

def toths(i):
s=str(i)
l=[]
ls=len(s)
for i in range(ls):
c=s[ls-i-1]
if i%3==0 and i<>0:
c=c+"."
l.append(c)
l.reverse()
return "".join(l)

[Diez B. Roggisch]

Re: Quick help needed: how to format an integer ?

durumdara@mailp ont.hu wrote:[color=blue]
> Hi !
>
> I need to convert some integer values.
>
> "1622" ->"1 622"
>
> or
>
> "10001234" -> ""10.001.23 4""
>
> So I need thousand separators.
>
> Can anyone helps me with a simply solution (like %xxx) ?[/color]

The module locale does what you need, look at ist docs, especially


locale.str
locale.format


Regards,

Diez

[Paul Rubin]

Re: Quick help needed: how to format an integer ?

"durumdara@mail pont.hu" <durumdara@mail pont.hu> writes:[color=blue]
> "10001234" -> ""10.001.23 4""
> So I need thousand separators.
> Can anyone helps me with a simply solution (like %xxx) ?[/color]

I think you're supposed to do a locale-specific conversion (I've never
understood that stuff). You could also do something like this:
[color=blue][color=green][color=darkred]
>>> def f(n):[/color][/color][/color]
if n < 0: return '-' + f(-n)
if n < 1000: return '%d' % n
return f(n//1000) + '.' + '%03d' % (n%1000)
[color=blue][color=green][color=darkred]
>>> f(3900900090090 9090000009)[/color][/color][/color]
'39.009.000.900 .909.090.000.00 9'[color=blue][color=green][color=darkred]
>>> f(39802183)[/color][/color][/color]
'39.802.183'[color=blue][color=green][color=darkred]
>>> f(3008)[/color][/color][/color]
'3.008'[color=blue][color=green][color=darkred]
>>> f(0)[/color][/color][/color]
'0'[color=blue][color=green][color=darkred]
>>> f(-9898239839)[/color][/color][/color]
'-9.898.239.839'[color=blue][color=green][color=darkred]
>>> f(12345)[/color][/color][/color]
'12.345'