Where can be a problem?

[Lad]

I use the following
###############
import re
Results=[]
data1='<a href="detailasp xmember=15015&m ode=advert" </a><a
href="detailasp xmember=15016&m ode=advert" </a><a
href="detailasp xmember=15017&m ode=advert" </a>'
ID = re.compile(r'^. *=(\d+)&.*$',re .MULTILINE)
Results=re.find all(ID,data1)
print Results
#############
to extract from data1 all numbers such as 15015,15016,150 17

But the program extracts only the last number 15017.
Why?
Thank you for help
La.

[Peter Otten]

Re: Where can be a problem?

Lad wrote:
[color=blue]
> I use the following
> ###############
> import re
> Results=[]
> data1='<a href="detailasp xmember=15015&m ode=advert" </a><a
> href="detailasp xmember=15016&m ode=advert" </a><a
> href="detailasp xmember=15017&m ode=advert" </a>'
> ID = re.compile(r'^. *=(\d+)&.*$',re .MULTILINE)
> Results=re.find all(ID,data1)
> print Results
> #############
> to extract from data1 all numbers such as 15015,15016,150 17
>
> But the program extracts only the last number 15017.
> Why?
> Thank you for help
> La.[/color]

After changing

data = '...
'

to

data = '''...
'''

I get all three numbers. There is probably another significant difference
between the posted code and the code you are actually running.

Peter

[Lad]

Re: Where can be a problem?

Peter,
I tried exactly this
########
import re
Results=[]
data1='<a href="detailasp xmember=15015&m ode=advert" </a><a
href="detailasp xmember=15016&m ode=advert" </a><a
href="detailasp xmember=15017&m ode=advert" </a>'
ID = re.compile(r'^. *=(\d+)&.*$',re .MULTILINE)
Results=re.find all(ID,data1)
print "Results are= ",Results
#########
and received
Results are= ['15017']

Not all numbers

What exactly did you get?
Thanks.
L.

[Peter Otten]

Re: Where can be a problem?

Lad wrote:
[color=blue]
> Peter,
> I tried exactly this
> ########
> import re
> Results=[]
> data1='<a href="detailasp xmember=15015&m ode=advert" </a><a
> href="detailasp xmember=15016&m ode=advert" </a><a
> href="detailasp xmember=15017&m ode=advert" </a>'
> ID = re.compile(r'^. *=(\d+)&.*$',re .MULTILINE)
> Results=re.find all(ID,data1)
> print "Results are= ",Results
> #########
> and received
> Results are= ['15017']
>
> Not all numbers
>
> What exactly did you get?[/color]

With /exactly/ this, I get:

$ cat lad1.py
import re
Results=[]
data1='<a href="detailasp xmember=15015&m ode=advert" </a><a
href="detailasp xmember=15016&m ode=advert" </a><a
href="detailasp xmember=15017&m ode=advert" </a>'
ID = re.compile(r'^. *=(\d+)&.*$',re .MULTILINE)
Results=re.find all(ID,data1)
print "Results are= ",Results
$ python lad1.py
File "lad1.py", line 3
data1='<a href="detailasp xmember=15015&m ode=advert" </a><a
^
SyntaxError: EOL while scanning single-quoted string

When I modify it to compile, I get /exactly/ this:

$ cat lad2.py
import re
Results=[]
data1='''<a href="detailasp xmember=15015&m ode=advert" </a><a
href="detailasp xmember=15016&m ode=advert" </a><a
href="detailasp xmember=15017&m ode=advert" </a>'''
ID = re.compile(r'^. *=(\d+)&.*$',re .MULTILINE)
Results=re.find all(ID,data1)
print "Results are= ",Results
$ python lad2.py
Results are= ['15015', '15016', '15017']

Peter

[Lad]

Re: Where can be a problem?

Thank you Peter for help.
The reason why it did not work was the fact that findall function
required CRLF among lines

[Paul McGuire]

Re: Where can be a problem?

Try this, its a bit more readable than your re.

from pyparsing import Word,nums,Liter al,replaceWith

data1='''<a href="detailasp xmember=15015&m-ode=advert" </a><a
href="detailasp xmember=15016&m ode=advert" </a><a
href="detailasp xmember=15017&m ode=advert" </a>'''

# a number is a word composed of nums, that is, the digits 0-9
# your search string is looking for a number between an '=' and '&'
EQUALS = Literal("=")
AMPER = Literal("&")
number = Word(nums)
hrefNumber = EQUALS + number + AMPER

# scanString is a generator, that returns matching tokens, start,
# and end location for each occurrence in the input string - we
# just care about the second token of each match
print [ tokens[1] for tokens,s,e in hrefNumber.scan String(data1) ]

# just for grins, here is how to convert the numbers to the
# string "###"
number.setParse Action( replaceWith("## #") )
print number.transfor mString(data1)


Prints:

['15015', '15016', '15017']
<a href="detailasp xmember=###&m-ode=advert" </a><a
href="detailasp xmember=###&mo de=advert" </a><a
href="detailasp xmember=###&mo de=advert" </a>

Download pyparsing at http://pyparsing.sourceforge.net.

-- Paul