Getting error

[youngpann42]

while($data_fetch=mysql_fetch_array($query_for_result))
{
    echo "<li>";
    echo '<a href="<?php echo $user_data['username']; ?>">' .
	substr($data_fetch[$db_tb_atr_name], 0,160). '</a>';
    echo "</li><hr/>";
}

but keeping getting this error

Parse error: syntax error, unexpected 'username' (T_STRING), expecting ',' or ';' in D:\xampp\htdocs \Register\searc h.php on line 39

can anyone help

[johny10151981]

yes you should get this error. I will give you a simple tip to avoid this dumb error. just follow the statement below:

while($data_fetch=mysql_fetch_assoc($query_for_res ult)) //array create both string and integer indexing. which is not very useful but unnecessary
{
echo "<li>";
echo '<a href="'.$user_data['username'].'">'.
substr($data_fetch[$db_tb_atr_name], 0,160). '</a>';
echo "</li><hr/>"; //I am not sure what you have wanted with this code but I have changed as i think it sould be. but still the output wont work properly cause your href will fail
}

now can you see and tell the difference?

[Rabbit]

You can use johny's method. But what you are trying to do can work if you use the correct syntax.

1) Variables are only interpreted within strings if the string is demarcated with double quotes.

2) When you want to interpret complex variables or constants in a string, you need to surround them in braces.

echo "{someArray['foo']}";