Whats wrong with my code

[ehpratah]

hi im having an error with my code can anyone help me try to fix my problem

the error is

Fatal error: Call to a member function diff() on a non-object in C:\xampp\htdocs\msicfinal\samp.php on line 12

and my code is

<?php
    /*These look like they are sent via form submit to this program*/
    $date1 = '2012-04-01'; // pick up date
    $date2 = '2012-05-27'; // return date
    $perday=2500;
    $permonth=52500;
    $perweek=15000;
    $datetime1 = ($date1);
    $datetime2 = ($date2);
    $interval = $datetime1->diff($datetime2); // the math for the difference
    $rest = $interval->format('%d days'); // this may contain weeks
    $week = intval($rest / 7); // weeks extracted from the above var.
    $mon = $interval->format('%m'); // The mon from formatting
    $day = intval($rest % 7); // This line MUST STAY to figure number of days
    $total = $mon * $permonth + $week * $perweek + $day * $perday;
    echo $total . '<br />';
    ?>

the purpose of this code is to compute the rate depending on the date

[Luuk]

from the manual:

<?php
$date1 = '2012-04-01'; // pick up date
$date2 = '2012-05-27'; // return date
$datetime1 = new DateTime($date1);
$datetime2 = new DateTime($date2);
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
?>

note the 'new DateTime'

[ehpratah]

hi i got it already but the problem is im getting wrong output

here's the code

<?php

$timezone = "Asia/Shanghai";
if(function_exists('date_default_timezone_set')) date_default_timezone_set($timezone);
echo date('d-m-Y H:i');

/*These look like they are sent via form submit to this program*/
$date1 = '2012-06-01'; // pick up date
$date2 = '2012-06-01'; // return date

$perday=2500;
$permonth=52500;
$perweek=15000;


$datetime1 = new DateTime($date1);
$datetime2 = new DateTime($date2);
$interval = $datetime1->diff($datetime2); // the math for the difference
$rest =  $interval->format('%d days');  // this may contain weeks
$week = intval($rest / 7);              // weeks extracted from the above var.                
$mon = $interval->format('%m');  // The mon from formatting
$day = intval($rest % 7);      // This line MUST STAY to figure number of days

echo 'week '.$week . '<br />';  // The echos are for your benifit and should be commented out or erased
echo 'day '.$day . '<br />';
echo ' months '.$mon .'<br />';


$total = $mon * $permonth + $week * $perweek + $day * $perday;
echo $total . '<br />';
?>

in the date part of this code i try to put the pick up date to 2012-06-01 the same with the return date..but im having a wrong output


it must be " 2500 "


but instead im getting this 0 for the total

22-06-2012 20:21
week 0
day 0
months 0
0


and also when i change the pick up date to 2012-06-01 and the return date to 2012-06-02

instead of getting "5000"

im getting

22-06-2012 20:28

week 0
day 2
months 0
2500




sorry if im bothering you it just that i really need a hand right now..

[Dormilich]

you may have not noted that $rest is a string, not a number and hence Math can be a little complicated.

[ehpratah]

well i got it already..with the help of some expert..

[Dormilich]

and what was the solution?