how to create and open directory in php directory dynamically?

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  • harini0590
    New Member
    • Apr 2012
    • 19

    how to create and open directory in php directory dynamically?

    here i have error as,"Undefined index: $opdir in C:\wamp\www\mum taj\sathya\dire ctory.php on line 15
    Directory does not exist"
    Code:
    <?php
    $dir=(mkdir("C:\wamp\www\upload3" , 0777));
    if($dir)
    {
       echo "Directory has been created successfully...";
    }
    else
    {
       echo "Failed to create directory...";
    }
    
    $opdir=opendir("C:\wamp\www\upload3");
    $uploaddir = $_SERVER['$opdir'];    	//Now here is the problem, what to give in the //place of '$opdir' ..
    echo (file_exists($uploaddir) && is_dir($uploaddir)) ? 'Directory path ok' : 'Directory does not exist';
    ?>
  • johny10151981
    Top Contributor
    • Jan 2010
    • 1059

    #2
    replace your all \ with \\ or instead just use / your problem would be solved

    Comment

    • harini0590
      New Member
      • Apr 2012
      • 19

      #3
      same problem exist in that after that change too.
      Code:
      <?php
      $dir=(mkdir("C:/wamp/www/upload34" , 0777));
      if($dir)
      {
         echo "Directory has been created successfully...";
      }
      else
      {
         echo "Failed to create directory...";
      }
      
      $opdir=opendir("C:/wamp/www/upload34");
      
      $uploaddir = $_SERVER['$opdir'];    	//Now here is the problem, what to give in the //place of '$opdir' ..
      echo (file_exists($uploaddir) && is_dir($uploaddir)) ? 'Directory path ok' : 'Directory does not exist';
      ?>

      Comment

      • saravana 786
        New Member
        • Apr 2012
        • 4

        #4
        if ur using windows or linux?

        Comment

        • johny10151981
          Top Contributor
          • Jan 2010
          • 1059

          #5
          start fixing from line 12

          at line 12 you have
          Code:
          $opdir=opendir("C:/wamp/www/upload34"); 
          //$opdir a resource, resource of directory.
          line 14
          Code:
          $uploaddir = $_SERVER['$opdir'];        //Now here is the problem, what to give in the //place of '$opdir' ..
          
          //here uploaddir would get resource $_SERVER don't exists. What does it contain nothing.
          read documentation for every function you have used in your php code

          Comment

          • harini0590
            New Member
            • Apr 2012
            • 19

            #6
            i use windowsXP and WAMP package...

            Comment

            Working...