how while loop value prints outside loop

[ditditsasa]

while (false !== ($sfname = readdir($dh))) {
  if (substr($sfname, 0, 1) == '.') continue;
  if ($sfname == 'CVS'            ) continue;
  $sitedir = "$OE_SITES_BASE/$sfname";
  if (!is_dir($sitedir)               ) continue;
  if (!is_file("$sitedir/sqlconf.php")) continue;
  $siteslist[$sfname] = $sfname;
    }	echo $sfname;//here not prints sfname value

the value not prints outside the loop. please help me

[dlite922]

You can't print a variable in the scope of the while loop outside it's scope, outside the while loop.

Your code iterates through the while loop and prints the last value that was assigned to $sfname.

[johny10151981]

@dilite922 I am confused about the information of while loop scope.
as far I know, while loop, if statement don’t have their own scope.

but about ditditsasa's problem, if the while condition does not satisfy in the first place in your print you won’t get anything.