$_SERVER["DOCUMENT_ROOT"] returns null or blank

akshaygvyas

New Member

Join Date: Jul 2011

Posts: 1
#1

$_SERVER["DOCUMENT_ROOT"] returns null or blank

Jul 29 '11, 01:53 PM

Hi,

I am trying to include some php files in one of my php page. It errors out saying:

Code:

Warning: include(/apps1/includes/getINIParamVal.php) [function.include]: failed to open stream: No such file or directory in D:\inetpub\vhosts\aadityatech.in\httpdocs\apps\apps1\index.php on line 9 Warning: include() [function.include]: Failed opening '/apps1/includes/getINIParamVal.php' for inclusion (include_path='.;./includes;./pear') in D:\inetpub\vhosts\aadityatech.in\httpdocs\apps\apps1\index.php on line 9

I checked twice, and found that my getINIParamVal. php in D:\inetpub\vhos ts\aadityatech. in\httpdocs\app s\apps1\include s.

I suspect that $_SERVER["DOCUMENT_R OOT"] variable returns the null value. I have included the file with following line:

Code:

include($_SERVER["DOCUMENT_ROOT"] . "/app1/includes/" . "getINIParamVal.php");

My document root in apache is:
D:\inetpub\vhos ts\aadityatech. in\httpdocs\app s

Please help. I would highly appreciate.

Thanks,
Akshay
Tags: $_server["document_root"], failed to open stream, include, php
Chris T

New Member

Join Date: Jul 2011

Posts: 5
#2

Jul 31 '11, 07:09 PM

at first look there's a mistake where you write /app1 in your include. There should be /apps1 , right ?
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