session management

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  • bikashliju
    New Member
    • Sep 2010
    • 9
    #1

    session management

    i have two programmes

    FORM.PHP
    Code:
    <?PHP
session_start();
?>
<html>
<body>
<form action="welcome.php" method="post">
firstname: <input type="text" name="fname" />
<input type="submit" />
</form>

</body>
</html>
    WELCOME.PHP
    Code:
    <?php
session_start();

if($_COOKIE[' PHPSESSID']=$_SESSION['PHPSESSID'])
{
 echo  $_POST["fname"];
}
else
{
echo"wrong session id";
}
?>
    but it gives me output wrong session id.
    Code:
    ($_COOKIE[' PHPSESSID']=$_SESSION['PHPSESSID'])
    i want to know whether this is a true condition or not , kindly inform if any syntactical error in it
    Last edited by Dormilich; Oct 12 '10, 08:43 AM.
    Tags: None
    • dlite922
      Recognized Expert Top Contributor
      • Dec 2007
      • 1586
      #2
      First of all you have a space in the cookie name.

      Second you're not doing a comparison, you're doing an assignment with a single equal sign. To compare the two and return true or false you need two (2) equal signs.

      This will test if the value of $foo equals the value of $bar:

      $bar == $foo

      This will put the value of $foo in to $bar so that they they contain the same value:

      $bar = $foo

      Let us know if that fixed it,



      Dan

        Comment

        • bikashliju
          New Member
          • Sep 2010
          • 9
          #3
          thanx sir
          u solved my problem ....

            Comment

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