The following code treats abcd as a variable and gives the error variable undefined in firebug
The following code gives the error XML Parsing Error at 1:44. Error 73: > required
I also have tried typecasting, taking abcd inside another PHP variable then passing the PHP variable. None seem to work.
Thank you for your help.
Regards,
Sunny.
Code:
return $data = "<a href='#' onclick='ajaxcall(abcd);'>".$name."</a>";
Code:
return $data = "<a href='#' onclick='ajaxcall('abcd');'>".$image.$tmp->name."</a>";
Thank you for your help.
Regards,
Sunny.
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