warning error message by using mysql_num in the mysql_fetch_array()

[santhanalakshmi]

Hi,

<?php
mysql_connect('localhost','root','');
mysql_select_db('test');
$query="select * from phonedirectory";
$result=mysql_query($query);
echo "One Way To Print";
echo "<br>";
while($row=mysql_fetch_array($result,mysql_num))
{
   echo $row[0]." ".$row[1]." ".$row[2]."<br>";
}

?>

Warning Error Message:

One Way To Print

Warning: mysql_fetch_arr ay() expects parameter 2 to be long, string given in F:\xampp installed\xampp \htdocs\mysql_f etch_demo1.php on line 8


thanks in advance.i dont know ,why am i facing this error

[Markus]

PHP's constants are case-sensitive.

mysql_num != MYSQL_NUM

Turn on error reporting to find problems like these.

error_reporting(-1);

[santhanalakshmi]

Thanks its working.....in php.ini file ,we should on ERROR_REPORTING (-1).Is it.

[Gears of Codes]

$query = "SELECT Name,Mobile,Website,Rating FROM grand_table order by 4";


// Passing Variables to execute and check

$result = mysql_query($query);

while( $data = mysql_fetch_array($result))
{
  echo("<tr><td>$data[0]</td><td>$data[1]</td><td>$data[2]</td><td>$data[3]</td></tr>");
  
 }

Hope by this query you can solve up your error...
I was too suffering from that problem but instead of using regular sqlquery of WHERE i had replaced that and using ORDER BY and also its not necessary to use WHERE and ORDER BY query coz thats the query in which we are ordering and selecting a specified field...

Thanks