Calling java script in PHP

Collapse
X
Collapse
 
  • Page of 3
  • Time
  • Show
Clear All
new posts
Previous 1 2 3 template Next
  • Markus
    Recognized Expert Expert
    • Jun 2007
    • 6092
    #16
    Originally posted by dheerajjoshim
    yeah Mark..

    I a gave that echo still it do not give anything.

    Regards
    Dheeraj Joshi
    Post the new code (using [code] tags).

      Comment

      • Dormilich
        Recognized Expert Expert
        • Aug 2008
        • 8694
        #17
        take it out of the switch(), currently that’s preventing the print.

          Comment

          • Markus
            Recognized Expert Expert
            • Jun 2007
            • 6092
            #18
            Originally posted by Dormilich
            actually… no. if you want to ‘execute’ a file you need to load/include it. and that doesn’t return a value…
            Code:
            // 4 different ways to include a file
include "file.php";
include_once "file.php";
require "file.php";
require_once "file.php";
            and backticks are not valid string delimiters.

            the only constructs able to return a value are variables, constants, functions, properties and methods (the latter 2 being special cases from to objects)
            Actually, back-ticks, like in other languages, do run the contents as a shell command.

            Code:
            printf("PHP is located at %s", `which php`);
// equivalent of doing
printf("PHP is located at %s", shell_exec('which php'));

              Comment

              • Dormilich
                Recognized Expert Expert
                • Aug 2008
                • 8694
                #19
                Originally posted by Markus
                Actually, back-ticks, like in other languages, do run the contents as a shell command.
                interesting, need to make a (mental) note of that.

                  Comment

                  • Dheeraj Joshi
                    Recognized Expert Top Contributor
                    • Jul 2009
                    • 1129
                    #20
                    Ok.. Markus... Then what does this return?

                    Code:
                    `php myfile.php`

                    A string or ............... ..?


                    Regards
                    Dheeraj Joshi

                      Comment

                      • Dormilich
                        Recognized Expert Expert
                        • Aug 2008
                        • 8694
                        #21
                        that depends on what’s inside myfile.php

                          Comment

                          • Dheeraj Joshi
                            Recognized Expert Top Contributor
                            • Jul 2009
                            • 1129
                            #22
                            You mean return type right?

                            Regards
                            Dheeraj Joshi

                              Comment

                              • Dormilich
                                Recognized Expert Expert
                                • Aug 2008
                                • 8694
                                #23
                                Originally posted by dheerajjoshim
                                You mean return type right?
                                yepp, though I don’t know if that’s return or echo. didn’t work with the CLI version of PHP so far.

                                  Comment

                                  • Dheeraj Joshi
                                    Recognized Expert Top Contributor
                                    • Jul 2009
                                    • 1129
                                    #24
                                    Generally languages have a tendency to print not to return unless we say it so.

                                    Regards
                                    Dheeraj Joshi

                                      Comment

                                      • Markus
                                        Recognized Expert Expert
                                        • Jun 2007
                                        • 6092
                                        #25
                                        It'll return a string, I imagine. Do a var_dump() on your $res variable.

                                          Comment

                                          • Dormilich
                                            Recognized Expert Expert
                                            • Aug 2008
                                            • 8694
                                            #26
                                            Originally posted by Markus
                                            Do a var_dump() on your $res variable.
                                            general advice: this is one of the things to be done first.

                                              Comment

                                              • gopan
                                                New Member
                                                • Apr 2009
                                                • 41
                                                #27
                                                Dear dheerajjoshim,
                                                If you're getting $res as 1 then look at the code line#9
                                                Code:
                                                case 1: "<scriptlanguage=javascript>
                                                and change it to

                                                Code:
                                                case 1: "<script language=\"javascript\">

                                                  Comment

                                                  • Markus
                                                    Recognized Expert Expert
                                                    • Jun 2007
                                                    • 6092
                                                    #28
                                                    Originally posted by gopan
                                                    Dear dheerajjoshim,
                                                    If you're getting $res as 1 then look at the code line#9
                                                    Code:
                                                    case 1: "<scriptlanguage=javascript>
                                                    and change it to

                                                    Code:
                                                    case 1: "<script language=\"javascript\">
                                                    As mentioned before, that won't work because you're not asking PHP to do anything with the string, it's the same as
                                                    Code:
                                                    <?php
"hi, my name is Mark";
                                                    which obviously will not output anything.

                                                      Comment

                                                      • gopan
                                                        New Member
                                                        • Apr 2009
                                                        • 41
                                                        #29
                                                        Originally posted by Markus
                                                        As mentioned before, that won't work because you're not asking PHP to do anything with the string, it's the same as
                                                        Code:
                                                        <?php
"hi, my name is Mark";
                                                        which obviously will not output anything.
                                                        yaa my bad Mark...

                                                        he need to add an echo before the quotes... I din't see that...

                                                        The corrected code will be...
                                                        Code:
                                                        <html>
<body>
<?php
 
$res = `php myfile.php`;
 
switch($res)
{
    case 1: 
       echo "<script language=\"javascript\"> 
            alert('Blah Blah')
        </script>";
        break;
    case 2: echo "Choice 2";
        break;
    case 3: echo "Choice 3";
        break;
    default:echo "No choice";
        break;
}
 
?>
</body>
</html>
                                                        and if $res is holding value one... the javascript will alert "blah blah"

                                                          Comment

                                                          • Jezternz
                                                            New Member
                                                            • Jan 2008
                                                            • 145
                                                            #30
                                                            didn't I say that above :(

                                                              Comment

                                                              Previous 1 2 3 template Next
                                                              Working...