Trouble fixing parse error, unexpected T_IF error

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  • Ciaroscuro
    New Member
    • Nov 2008
    • 2
    #1

    Trouble fixing parse error, unexpected T_IF error

    Howdy -
    In setting up a registration form, I'd like to keep any correct entries on the form (make them sticky).

    The Registration Form is "included" and has the the following structure:

    Code:
    <body>
 <?php
    echo "	<p>

    <form action=$_SERVER[PHP_SELF] method='POST'>
       <table width='95%' border='0' cellspacing='0' cellpadding='2'> 

         <tr><td></td><td>Please fill in all information.</td></tr>
	 	
          <tr><td align='right'><b>First Name:</b></td>
 	 <td><input type='text' name='FirstName' size='35' 
                maxlength='35'  value="if (isset($_POST['FirstName']))
                     {echo $_POST['FirstName']}; "></td></tr>

	
          </table>
        <input type='hidden' name='submitted' value='yes'>
      </form>
  </p> 
 ?>
</body>
    This generates the following error message:
    parse error, unexpected T_IF, expecting ',' or ';' in /html/RegistrationFor m1.php on line 12

    How does one punctuate the "if (isset...) to provide the indicated ", or ;" the compiler is looking for?
    Would appreciate any help or suggestions.

    Thanks
    Last edited by Banfa; Nov 11 '08, 11:39 AM. Reason: Added [code]...[/code] round the code
    Tags: None
    • Dormilich
      Recognized Expert Expert
      • Aug 2008
      • 8694
      #2
      you missed the ; in the execution block (line 34) and put it outside the brackets (just swap } and ;)
      [PHP]if (...)
      {
      echo $var; // semicolon here
      } // not here[/PHP]
      note: a proper indentation style may increase readability a lot. you may consider to separate markup and processing by first evaluating all expressions and insert the results in your markup.

      regards

        Comment

        • Banfa
          Recognized Expert Expert
          • Feb 2006
          • 9067
          #3
          Ciaroscuro,

          your code will be better formated and easier for our experts to read if you put &#91;code]...[/code] tags round it like I have done for you now.

          Please read our posting guidelines

          Banfa
          Administrator

            Comment

            • Ciaroscuro
              New Member
              • Nov 2008
              • 2
              #4
              Dormilich & Banfa -

              Thank you for your responses. I tried changing the position of the semi-colon but that didn't change the error message. I ended up converting from a PHP echo form to a staight HTML form with <?php ...?> phrases for the

              Code:
              <form action="<?php $_SERVER[PHP_SELF];?>" method="POST">
              and

              Code:
              <tr><td align='right'><b>First Name:</b></td>
    <td><input type='text' name='FirstName' size='35'
          maxlength='35' value="<?php if(isset($_POST['FirstName']))
  	echo $_POST['FirstName'];?>"/></td></tr>
              to get the sticky Value attribute to work.

              Still haven't figured out why the <?php echo format didn't work, but this other approach does, so I'm making forward progress again. Thanks.
              Last edited by Markus; Nov 12 '08, 11:45 AM. Reason: added # tags

                Comment

                • Markus
                  Recognized Expert Expert
                  • Jun 2007
                  • 6092
                  #5
                  Originally posted by Ciaroscuro
                  Dormilich & Banfa -

                  Thank you for your responses. I tried changing the position of the semi-colon but that didn't change the error message. I ended up converting from a PHP echo form to a staight HTML form with <?php ...?> phrases for the

                  Code:
                  <form action="<?php $_SERVER[PHP_SELF];?>" method="POST">
                  and

                  Code:
                  <tr><td align='right'><b>First Name:</b></td>
    <td><input type='text' name='FirstName' size='35'
          maxlength='35' value="<?php if(isset($_POST['FirstName']))
  	echo $_POST['FirstName'];?>"/></td></tr>
                  to get the sticky Value attribute to work.

                  Still haven't figured out why the <?php echo format didn't work, but this other approach does, so I'm making forward progress again. Thanks.
                  Ciaroscuro, please pay attention to post No.3 - it makes your post a lot easier to read for our experts if you use code tags.

                  Moderator.

                    Comment

                    • Dormilich
                      Recognized Expert Expert
                      • Aug 2008
                      • 8694
                      #6
                      Originally posted by Ciaroscuro
                      I tried changing the position of the semi-colon but that didn't change the error message.
                      checked your code snippet (with subethaedit using php) and I didn't get a parser error. judging from that, the code should be running fine.

                      regards

                      note: could verify the error message for the original code (just if you wonder...)

                        Comment

                        • Markus
                          Recognized Expert Expert
                          • Jun 2007
                          • 6092
                          #7
                          You can't have an IF statement inside and echo statement. Won't work. Create a function that does your IF checks and then RETURNs a value.

                          Code:
                          value=" . some_function() . "

                            Comment

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