Using FTP via PHP

[adamjblakey]

Hi,

I am trying to upload some files using ftp via php.

I have built a function which should work as far as i can see but it isn't. Can anyone see why this would not work?


[PHP]
function ftpupload($file , $destination){

// set up the settings
$ftp_server = "ftp.".$_SESSIO N['domain'];
$ftpuser = $_SESSION['user'];
$ftppass = $_SESSION['pass'];

// delete the below variables if you decide to use a form.
$source_file = $file;
$destination_fi le = $destination;

// set up basic connection
$conn_id = ftp_connect($ft p_server);

// login with username and password
$login_result = ftp_login($conn _id, $ftpuser, $ftppass);

ftp_put($conn_i d, "$destination_f ile", "$source_fi le", FTP_BINARY); // the ftp function

// close the connection
ftp_close($conn _id);

}
[/PHP]

Then:

[PHP]
ftpupload($rand _name.$file_ext , "/uploads/images/thumbs/");
[/PHP]

Any Ideas?
Cheers,
Adam

[code green]

[PHP]$ftp_server = "ftp.".$_SESSIO N['domain']; [/PHP] You don't need the 'ftp' bit for [PHP]ftp_connect($ft p_server); [/PHP]Just the address.
Whether you use the IP address or the hostname is trial and error.
It depends on the ftp set up

[adamjblakey]

Thank you for your reply,

I have tried using the IP but this did not work either. I have changed the script a bit now to see where it is failing and it seems to connect fine to the FTP. The problem is with sending the file.

[PHP]
function ftpupload($file , $destination){

// set up the settings
$ftp_server = "ftp.".$_SESSIO N['domain'];
$ftpuser = $_SESSION['user'];
$ftppass = $_SESSION['pass'];

// delete the below variables if you decide to use a form.
$source_file = $file;
$destination_fi le = $destination;

// set up basic connection
$conn_id = ftp_connect($ft p_server);

// login with username and password
$login_result = ftp_login($conn _id, $ftpuser, $ftppass);

//Check if login was successful
if (!$login_result ){
echo "Sorry there is currently a problem with our servers, please notify use of this problem or try again later.";
exit();
}

$upload = ftp_put($conn_i d, $destination_fi le, $source_file, FTP_BINARY); // the ftp function

// check upload status
if (!$upload) {
echo "FTP upload has failed!";
exit();
} else {
echo "Uploaded $source_file to $ftp_server as $destination_fi le";
exit();
}

// close the connection
ftp_close($conn _id);

}
[/PHP]

I keep getting this erro: FTP upload has failed!
Cheers,
Adam

[code green]

I would suggest incorrect file path to either $file, $destination.
Echo these values to see what is in there and check the source and remote directories exist.
Be aware the ftp address is a specific folder and all paths are relative to that folder

[adamjblakey]

Right i have given up doing it that way, i have however found a way that does upload but when the file is uploaded on the server it is 0kb but at least it is uploading.

[PHP]
function ftpupload($file ){

$ch = curl_init();
$localfile = $file;
$fp = fopen($localfil e, 'r');
curl_setopt($ch , CURLOPT_URL, 'ftp://'.$_SESSION['name'].':'.$_SESSION['pass'].'@87.229.14.87/httpdocs/uploads/images/thumbs/'.$file);
curl_setopt($ch , CURLOPT_UPLOAD, 1);
curl_setopt($ch , CURLOPT_INFILE, $fp);
curl_setopt($ch , CURLOPT_INFILES IZE, filesize($local file));
curl_exec ($ch);
$error_no = curl_errno($ch) ;
curl_close ($ch);
if ($error_no == 0) {
print 'File uploaded succesfully.';
} else {
print 'File upload error.';
}

}
[/PHP]

Any Ideas why it is 0kb?

[code green]

Could be a few things.
File space full.
Blocked by firewall.
Corrupted file
Not really hph problem.
You original function indicated a file path problem.
Did you investigate this?

[adamjblakey]

Thank you for your reply, the disk space is not the problem as i have check this and it is fine. I don't have a firewall on so this cannot be the problem either. The file is not corrupt either.

I did investigate this but i could not find out the problem even after hours of looking at it, and was feeling like i was going in circles.

Cheers,
Adam

[adamjblakey]

Hi,

I have come up with the solution to this now but have a little problem.

I am now using this to upload the images.

[PHP]
function ftpupload($file , $img_tmp, $path){

$message = '';
if ($ftp = ftp_connect($_S ESSION['ddomain'])) {
if (ftp_login($ftp , $_SESSION['dname'], $_SESSION['dpass'])) {
ftp_pasv($ftp, true);
if (ftp_put($ftp, $path . $file,
$img_tmp, FTP_BINARY)) {
$message = "File uploaded";
} else {
die("Could not upload file");
}
} else {
die("Could not login to FTP account");
}
} else {
die("Could not connect to FTP server");
}
}
[/PHP]

Now if i pass an image to this via a form it is fine, the problem i am having is i am running this function with another function which resizes images and renames it but the ftp function relies on an input of ['name'] and ['tmp_name'] to upload the image.

This is the function for image rename and resize:

[PHP]
function uploadimage($va lue){
$file_type = $value['type'];
$file_name = $value['name'];
$file_size = $value['size'];
$file_tmp = $value['tmp_name'];

//check file extension
$ext = strrchr($file_n ame,'.');
$ext = strtolower($ext );
if (($extlimit == "yes") && (!in_array($ext ,$limitedext))) {
echo "Wrong file extension. <br>--<a href=\"$_SERVER[PHP_SELF]\">back</a>";
exit();
}

//get the file extension.
$getExt = explode ('.', $file_name);
$file_ext = $getExt[count($getExt)-1];

//create a random file name
$rand_name = md5(time());
$rand_name= rand(0,99999999 9);
//get the new width variable.
$ThumbWidth = 175;
$ImgWidth = 700;

//keep image type
if($file_size){
if($file_type == "image/pjpeg" || $file_type == "image/jpeg"){
$new_img = imagecreatefrom jpeg($file_tmp) ;
}elseif($file_t ype == "image/x-png" || $file_type == "image/png"){
$new_img = imagecreatefrom png($file_tmp);
}elseif($file_t ype == "image/gif"){
$new_img = imagecreatefrom gif($file_tmp);
}
//list width and height and keep height ratio.
list($width, $height) = getimagesize($f ile_tmp);
$imgratio=$widt h/$height;
if ($imgratio>1){
$newwidth = $ThumbWidth;
$newheight = $ThumbWidth/$imgratio;
$newwidth2 = $ImgWidth;
$newheight2 = $ImgWidth/$imgratio;

}else{
$newheight = $ThumbWidth;
$newwidth = $ThumbWidth*$im gratio;

$newheight2 = $ImgWidth;
$newwidth2 = $ImgWidth*$imgr atio;
}


$resized_img = imagecreatetrue color($newwidth , $newheight);
$resized_img2 = imagecreatetrue color($newwidth 2, $newheight2);
imagecopyresize d($resized_img, $new_img, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
imagecopyresize d($resized_img2 , $new_img, 0, 0, 0, 0, $newwidth2, $newheight2, $width, $height);

//save image
ftpupload($file _name, $file_tmp, "httpdocs/uploads/images/thumbs/");
ftpupload($file _name, $file_tmp, "httpdocs/uploads/images/big/");

imagedestroy($r esized_img);
imagedestroy($r esized_img2);
imagedestroy($n ew_img);


}
$value = "$rand_name.$fi le_ext";
return $value;
}
[/PHP]

This works fine as it is now as i am just passing the real image name but i don't know how to do it with the renamed image.

Any ideas?
Cheers,
Adam