Why no error?

[Andrew G. Koptyaev]

Why no error on this code?

<?php
for ($i=0;$i<5;++$i )
{
if ($i==2)
continue
print "$i\n";
}
?>

Output is "2".
May be true must be "continue;" ?

[703designs]

Re: Why no error?

That's weird and interesting. You're right, you need the semicolon.

On Sep 23, 1:20 pm, "Andrew G. Koptyaev" <kopty...@gmail .comwrote:

Why no error on this code?
>
<?php
for ($i=0;$i<5;++$i )
{
 if ($i==2)
  continue
 print "$i\n";}
>
?>
>
Output is "2".
May be true must be "continue;" ?

[Michael Fesser]

Re: Why no error?

..oO(703designs )

>That's weird and interesting.

It's documented behaviour. The example was taken from the manual and
describes a situation which you should avoid.

Maybe it becomes clearer with a little rearrangement, it's still the
same code:

<?php
for ($i = 0; $i < 5; ++$i) {
if ($i == 2) {
continue print "$i\n";
}
}
?>

Since print is a special language construct and always returns 1, the
above is equivalent to

<?php
for ($i = 0; $i < 5; ++$i) {
if ($i == 2) {
print "$i\n";
continue 1;
}
}
?>

http://www.php.net/manual/en/control-structures.continue.php

>You're right, you need the semicolon.

Yep.

Micha