oop question

[jmDesktop]

http://php.net/manual/en/language.oop5.visibility.php

Why does it print out below like it says it does? Why doesn't it
print out just foo's methods?

Thanks.

class Bar
{
public function test() {
$this->testPrivate( );
$this->testPublic() ;
}

public function testPublic() {
echo "Bar::testPubli c\n";
}

private function testPrivate() {
echo "Bar::testPriva te\n";
}
}

class Foo extends Bar
{
public function testPublic() {
echo "Foo::testPubli c\n";
}

private function testPrivate() {
echo "Foo::testPriva te\n";
}
}

$myFoo = new foo();
$myFoo->test(); // Bar::testPrivat e
// Foo::testPublic

[jmDesktop]

Re: oop question

On Sep 16, 12:25 pm, jmDesktop <needin4mat...@ gmail.comwrote:

http://php.net/manual/en/language.oop5.visibility.php

>
Why does it print out below like it says it does?    Why doesn't it
print out just foo's methods?
>
Thanks.
>
class Bar
{
    public function test() {
        $this->testPrivate( );
        $this->testPublic() ;
    }
>
    public function testPublic() {
        echo "Bar::testPubli c\n";
    }
>
    private function testPrivate() {
        echo "Bar::testPriva te\n";
    }
>
}
>
class Foo extends Bar
{
    public function testPublic() {
        echo "Foo::testPubli c\n";
    }
>
    private function testPrivate() {
        echo "Foo::testPriva te\n";
    }
>
}
>
$myFoo = new foo();
$myFoo->test(); // Bar::testPrivat e
                // Foo::testPublic

because foo's is private and bar can't see it. but when I changed
foo's to public testPrivate, it still showed bar's. I had to make the
both public to see foo's.

[Jerry Stuckle]

Re: oop question

jmDesktop wrote:

On Sep 16, 12:25 pm, jmDesktop <needin4mat...@ gmail.comwrote:

>http://php.net/manual/en/language.oop5.visibility.php
>>
>Why does it print out below like it says it does? Why doesn't it
>print out just foo's methods?
>>
>Thanks.
>>
>class Bar
>{
> public function test() {
> $this->testPrivate( );
> $this->testPublic() ;
> }
>>
> public function testPublic() {
> echo "Bar::testPubli c\n";
> }
>>
> private function testPrivate() {
> echo "Bar::testPriva te\n";
> }
>>
>}
>>
>class Foo extends Bar
>{
> public function testPublic() {
> echo "Foo::testPubli c\n";
> }
>>
> private function testPrivate() {
> echo "Foo::testPriva te\n";
> }
>>
>}
>>
>$myFoo = new foo();
>$myFoo->test(); // Bar::testPrivat e
> // Foo::testPublic

>
because foo's is private and bar can't see it. but when I changed
foo's to public testPrivate, it still showed bar's. I had to make the
both public to see foo's.
>

That is correct operation. Even though Foo's method is public, Bar's is
private. So Bar::test() only looks at the private function.

To overload a function in a derived class, both base and derived class
functions must be public.

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===

[jmDesktop]

Re: oop question

On Sep 16, 12:54 pm, Jerry Stuckle <jstuck...@attg lobal.netwrote:

jmDesktop wrote:

On Sep 16, 12:25 pm, jmDesktop <needin4mat...@ gmail.comwrote:

>http://php.net/manual/en/language.oop5.visibility.php

>

Why does it print out below like it says it does?    Why doesn't it
print out just foo's methods?

>

Thanks.

>

class Bar
{
    public function test() {
        $this->testPrivate( );
        $this->testPublic() ;
    }

>

    public function testPublic() {
        echo "Bar::testPubli c\n";
    }

>

    private function testPrivate() {
        echo "Bar::testPriva te\n";
    }

>

}

>

class Foo extends Bar
{
    public function testPublic() {
        echo "Foo::testPubli c\n";
    }

>

    private function testPrivate() {
        echo "Foo::testPriva te\n";
    }

>

}

>

$myFoo = new foo();
$myFoo->test(); // Bar::testPrivat e
                // Foo::testPublic

>

because foo's is private and bar can't see it.  but when I changed
foo's to public testPrivate, it still showed bar's.  I had to make the
both public to see foo's.

>
That is correct operation.  Even though Foo's method is public, Bar's is
private.  So Bar::test() only looks at the private function.
>
To overload a function in a derived class, both base and derived class
functions must be public.
>
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstuck...@attgl obal.net
=============== ===- Hide quoted text -
>
- Show quoted text -

Is that just the way that PHP handles overriding (it isn't really
overloading is it)? I don't remember that way being anything specific
for oop. I know some have the word virtual and overrid like C#. Or
the derived just overrides by default. I think Java does it that way.

[Michael Fesser]

Re: oop question

..oO(Jerry Stuckle)

>That is correct operation. Even though Foo's method is public, Bar's is
>private. So Bar::test() only looks at the private function.
>
>To overload a function in a derived class, both base and derived class
>functions must be public.

Or protected.

Micha

[Jerry Stuckle]

Re: oop question

jmDesktop wrote:

On Sep 16, 12:54 pm, Jerry Stuckle <jstuck...@attg lobal.netwrote:

>jmDesktop wrote:

>>On Sep 16, 12:25 pm, jmDesktop <needin4mat...@ gmail.comwrote:
>>>http://php.net/manual/en/language.oop5.visibility.php
>>>Why does it print out below like it says it does? Why doesn't it
>>>print out just foo's methods?
>>>Thanks.
>>>class Bar
>>>{
>>> public function test() {
>>> $this->testPrivate( );
>>> $this->testPublic() ;
>>> }
>>> public function testPublic() {
>>> echo "Bar::testPubli c\n";
>>> }
>>> private function testPrivate() {
>>> echo "Bar::testPriva te\n";
>>> }
>>>}
>>>class Foo extends Bar
>>>{
>>> public function testPublic() {
>>> echo "Foo::testPubli c\n";
>>> }
>>> private function testPrivate() {
>>> echo "Foo::testPriva te\n";
>>> }
>>>}
>>>$myFoo = new foo();
>>>$myFoo->test(); // Bar::testPrivat e
>>> // Foo::testPublic
>>because foo's is private and bar can't see it. but when I changed
>>foo's to public testPrivate, it still showed bar's. I had to make the
>>both public to see foo's.

>That is correct operation. Even though Foo's method is public, Bar's is
>private. So Bar::test() only looks at the private function.
>>
>To overload a function in a derived class, both base and derived class
>functions must be public.
>>
>--
>============== ====
>Remove the "x" from my email address
>Jerry Stuckle
>JDS Computer Training Corp.
>jstuck...@attg lobal.net
>============== ====- Hide quoted text -
>>
>- Show quoted text -

>
Is that just the way that PHP handles overriding (it isn't really
overloading is it)? I don't remember that way being anything specific
for oop. I know some have the word virtual and overrid like C#. Or
the derived just overrides by default. I think Java does it that way.
>

That's the way C++, Java and SmallTalk handle it, and it's a basic
principal of OO. I don't know how c# does it - but it wouldn't surprise
me if it didn't follow OO principles.

And it isn't really overriding, either - it's actually polymorphism.
But I don't like to use too many long words because of some of the
trolls in this newsgroup :-).

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===