loop last six months

[Chris]

I don't understand why the code below is behaving strangely...any
ideas. It outputs August, July, July, May, May, March?

Thanks,

Chris



echo "<select name=\"month\"> \n";
for($i = 0; $i < 6; $i++) {
$str_lastmonth = date("F", mktime(0,0,0,da te("m")-
$i,date("d"),da te("Y")));
$val_lastmonth = date("m", mktime(0,0,0,da te("m")-
$i,date("d"),da te("Y")));
echo "<option value=\"{$val_l astmonth}\">${s tr_lastmonth}</option>\n";
}
echo "</select>\n";

[Paul Herber]

Re: loop last six months

On Sun, 31 Aug 2008 04:12:40 -0700 (PDT), Chris
<matchett123@go oglemail.comwro te:

>I don't understand why the code below is behaving strangely...any
>ideas. It outputs August, July, July, May, May, March?
>
>Thanks,
>
>Chris
>
>
>
>echo "<select name=\"month\"> \n";
>for($i = 0; $i < 6; $i++) {
>$str_lastmon th = date("F", mktime(0,0,0,da te("m")-
>$i,date("d"),d ate("Y")));
>$val_lastmon th = date("m", mktime(0,0,0,da te("m")-
>$i,date("d"),d ate("Y")));
>echo "<option value=\"{$val_l astmonth}\">${s tr_lastmonth}</option>\n";
>}
>echo "</select>\n";

It would seemingly have worked a few days ago!
Today is the 31st of August, your loop tries to work with the current
day number of the last six months, some of these don't exist. i.e.
31st June doesn't exist, it gets converted to 1st July, hence you get
two instances of July.



--
Regards, Paul Herber, Sandrila Ltd.
Unicode characters http://www.diacrit.sandrila.co.uk/

[Chris]

Re: loop last six months

On 31 Aug, 13:50, Paul Herber <SubstituteMyFi rstNameH...@phe rber.com>
wrote:

On Sun, 31 Aug 2008 04:12:40 -0700 (PDT), Chris
>
>
>
>
>
<matchett...@go oglemail.comwro te:

I don't understand why the code below is behaving strangely...any
ideas. It outputs August, July, July, May, May, March?

>

Thanks,

>

Chris

>

echo "<select name=\"month\"> \n";
for($i = 0; $i < 6; $i++) {
$str_lastmonth = date("F", mktime(0,0,0,da te("m")-
$i,date("d"),da te("Y")));
$val_lastmonth = date("m", mktime(0,0,0,da te("m")-
$i,date("d"),da te("Y")));
echo "<option value=\"{$val_l astmonth}\">${s tr_lastmonth}</option>\n";
}
echo "</select>\n";

>
It would seemingly have worked a few days ago!
Today is the 31st of August, your loop tries to work with the current
day number of the last six months, some of these don't exist. i.e.
31st June doesn't exist, it gets converted to 1st July, hence you get
two instances of July.
>
--
Regards, Paul Herber, Sandrila Ltd.
Unicode characters              http://www.diacrit.sandrila..co.uk/- Hide quoted text -
>
- Show quoted text -

Thanks Paul,

I see the problem now...I will assign an arbitary day date as all I am
looking for is the month details.

Cheers,

Chris

[Jerry Stuckle]

Re: loop last six months

Chris wrote:

I don't understand why the code below is behaving strangely...any
ideas. It outputs August, July, July, May, May, March?
>
Thanks,
>
Chris
>
>
>
echo "<select name=\"month\"> \n";
for($i = 0; $i < 6; $i++) {
$str_lastmonth = date("F", mktime(0,0,0,da te("m")-
$i,date("d"),da te("Y")));
$val_lastmonth = date("m", mktime(0,0,0,da te("m")-
$i,date("d"),da te("Y")));
echo "<option value=\"{$val_l astmonth}\">${s tr_lastmonth}</option>\n";
}
echo "</select>\n";
>

Today (8/31), your mktime expression comes out to:

8/31/2008
7/31/2008
6/31/2008
5/31/2008
4/31/2008
3/31/2008

Since 6/31/2008 and 4/31/2008 don't exist, PHP adjusts to the equivalent
(from the start of the year), which would be 5/1/2008 and 5/1/2008,
respectively.

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===

[Curtis]

Re: loop last six months

Chris wrote:

I don't understand why the code below is behaving strangely...any
ideas. It outputs August, July, July, May, May, March?
>
Thanks,
>
Chris
>
>
>
echo "<select name=\"month\"> \n";
for($i = 0; $i < 6; $i++) {
$str_lastmonth = date("F", mktime(0,0,0,da te("m")-
$i,date("d"),da te("Y")));
$val_lastmonth = date("m", mktime(0,0,0,da te("m")-
$i,date("d"),da te("Y")));
echo "<option value=\"{$val_l astmonth}\">${s tr_lastmonth}</option>\n";
}
echo "</select>\n";

Just me, but I'd rather clutter up the for loop logic a little than
the block. Also, no need to include the year, if you mean the current
year.

$monthsPrior = 6;

for ( $i = date('n'); $i (date('n') - $monthsPrior); $i-- ) {
$monthFull = date('F', mktime(0,0,0,$i ));
$monthVal = date('m', mktime(0,0,0,$i ));

// ...
}

--
Curtis