How to tale only hour from the date time

[ghjk]

I want to take only the hour from the date time field. For that first i apply the explode.[PHP]$Query1 = explode(" ",$row['Date']);[/PHP]
output:13:30:00 13:30:0016:20:0 016:20:00(This include hour:minutes:se conds)
And now i want to extract only first 2 digit(hour).
ex:13,13,16,16
HOw can i do that? Please help me.

[Brosert]

try

date('h',$row['Date']);

if the sql stores the date as a single int....
if the Date field is a String representation, you may like to first convert to a time object, using:

$temp=strtotime($row['Date']);
$hour=date('h',$temp);

note: h will give you the hour in 12 hr format - H will give 24hr format

you could also try to extract the hour yourself by manipulating the string.....

http://us3.php.net/date

[ghjk]

try

date('h',$row['Date']);

if the sql stores the date as a single int....
if the Date field is a String representation, you may like to first convert to a time object, using:

$temp=strtotime($row['Date']);
$hour=date('h',$temp);

note: h will give you the hour in 12 hr format - H will give 24hr format

you could also try to extract the hour yourself by manipulating the string.....

http://us3.php.net/date

I did it. But got only 20. This is my code.[PHP]
$Date= "13:30:0013:30: 0016:20:0016:20 :00";
date('H',$row['Date']);

$temp=strtotime ($row['Date']);
$hour=date('H', $temp);
echo "$hour";[/PHP]

[Brosert]

Why are there 4 seperate Times in the field??

I think you will have to manipulate the string yourself....
firtunately, the field should always be the same size. You can use the php substr method which takes string, offset and lengh as arguments....eg , the first hour would be

$hr1=substr($Date,0,2);

the second would be

$h2=substr($Date8,2);

etc...
If you wanted to, you could store them all in an Array - and use a loop to calculate them....