Show a missing page error

[hsriat]

Assume this case:

• User requests for a page: my-page.php.
• If the page is available, the browser shows the page.
• But if the page is missing, the browser gets redirected to a page with address:
  missing_page.ph p?page=my-page.php

How can this be done?

[nashruddin]

If you are using Apache, provide .htaccess file like this:

ErrorDocument 401 error.php?code=401
ErrorDocument 403 error.php?code=403
ErrorDocument 404 error.php?code=404

The configuration above will display error.php for HTTP error 401, 403 and 404. And error.php might looks something like this:

<?php
switch($_GET['code']) {
  case '401':
    print "Error 401 - Authentication Required!";
    break;
  case '403':
    print "Error 403 - Access Forbidden!";
    break;
  case '404':
    print "You have requested for page " . $_SERVER['REQUEST_URI'] . " which doesn't exist.";
    break;
}
?>

[hsriat]

So I think I need this as in .htaccess

[code=Apache]ErrorDocument 404 missing_page.ph p?page=$_SERVER['REQUEST_URI'][/code]

[realin]

So I think I need this as in .htaccess

[code=Apache]ErrorDocument 404 missing_page.ph p?page=$_SERVER['REQUEST_URI'][/code]

$_SERVER['REQUEST_URI'] wont work in .htaccess i guess

[hsriat]

$_SERVER['REQUEST_URI'] wont work in .htaccess i guess

pretty good point!!!

Then how to solve this?

[EDIT: Solved: Instead of using $_GET['page'] in missing_page.ph p, I can utilize $_SERVER['REQUEST_URI']]