Directory $path syntax problem

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  • WPW07
    #1

    Directory $path syntax problem

    Hello,

    I have a script that lists the contents of a directory. It was
    working properly until we had to change the directory that it reads
    from.

    The path to this script is:

    /home/n/mu1/database/refresh.php.

    I'd like it to list the contents in the main directory of the site:
    mu1

    So I have this code to list (up one level from the script):

    $path = "../mu1/";
    $dir_handle = opendir($path) or die("Unable to open directory $path");

    But I get this error message when I try to run it:

    Warning: opendir(../mu1/) [function.opendi r]: failed to open dir: No
    such file or directory in /home/n/mu1/database/refresh.php on line 19
    Unable to open directory ../mu1/

    Any idea what I'm doing wrong?

    Thanks!

    Tags: None
    • ZeldorBlat
      #2
      Re: Directory $path syntax problem

      On Mar 4, 12:06 pm, WPW07 <wwisnie...@gma il.comwrote:
      Hello,
      >
      I have a script that lists the contents of a directory. It was
      working properly until we had to change the directory that it reads
      from.
      >
      The path to this script is:
      >
      /home/n/mu1/database/refresh.php.
      >
      I'd like it to list the contents in the main directory of the site:
      mu1
      >
      So I have this code to list (up one level from the script):
      >
      $path = "../mu1/";
      $dir_handle = opendir($path) or die("Unable to open directory $path");
      >
      But I get this error message when I try to run it:
      >
      Warning: opendir(../mu1/) [function.opendi r]: failed to open dir: No
      such file or directory in /home/n/mu1/database/refresh.php on line 19
      Unable to open directory ../mu1/
      >
      Any idea what I'm doing wrong?
      >
      Thanks!
      From your location in /home/n/mu1/database/refresh.php the value
      of ../ would be the directory above /database which is /mu1. So, "../
      mu1" is really /home/n/mu1/mu1/ which probably isn't what you want.
      If you're inside /database you get to mu1 with ../ by itself.

        Comment

        • WPW07
          #3
          Re: Directory $path syntax problem

          On Mar 4, 12:45 pm, ZeldorBlat <zeldorb...@gma il.comwrote:
          On Mar 4, 12:06 pm, WPW07 <wwisnie...@gma il.comwrote:
          >
          >
          >
          Hello,
          >
          I have a script that lists the contents of a directory. It was
          working properly until we had to change the directory that it reads
          from.
          >
          The path to this script is:
          >
          /home/n/mu1/database/refresh.php.
          >
          I'd like it to list the contents in the main directory of the site:
          mu1
          >
          So I have this code to list (up one level from the script):
          >
          $path = "../mu1/";
          $dir_handle = opendir($path) or die("Unable to open directory $path");
          >
          But I get this error message when I try to run it:
          >
          Warning: opendir(../mu1/) [function.opendi r]: failed to open dir: No
          such file or directory in /home/n/mu1/database/refresh.php on line 19
          Unable to open directory ../mu1/
          >
          Any idea what I'm doing wrong?
          >
          Thanks!
          >
          From your location in /home/n/mu1/database/refresh.php the value
          of ../ would be the directory above /database which is /mu1. So, "../
          mu1" is really /home/n/mu1/mu1/ which probably isn't what you want.
          If you're inside /database you get to mu1 with ../ by itself.

          Thank you. That fixed it!

            Comment

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