How to call function

[nma]

Hi

I have a function call getMovieLength. How do I call the function so that I can calculate the $cellwidth variable in the php code below. It shows error message like below
"Notice: Use of undefined constant movieLength - assumed 'movieLength' in C:\htdocs\..\MB 2search.php on line 779
Warning: Division by zero in C:\htdocs\..\MB 2search.php on line 784"


[HTML]
$movie = $db->get_row("selec t * from Movie where movieID='" . $_GET['movieID'] . "'");
....
....

function getMovieLength( lengthString) {
times = lengthString.sp lit(':');
return (((parseInt(tim es[0]) * 60) + parseInt(times[1])) * 60) + parseInt(times[2]);
}

...
...
var movieLength = getMovieLength( "<?php echo $movie->duration?>") ;
...
...
[/HTML]

[PHP]
<?php

$allEvents = $db->get_results("S ELECT * FROM EventsShotsStar tAndStopFrames where movieID='" . $_GET['movieID'] . "' and eventCategory = 'Dialogue'");
$prevTime = 0;
$movieLengthTim eline = (movieLength * 30);

foreach($allEve nts as $timeline)
{
$frameDuration = ($timeline->shotStartFrame ) - $prevTime;
$cellwidth = round(($frameDu ration * 650)/ $movieLengthTim eline);//round here
?>

<td width="<?php echo ($cellwidth); ?>" height="17" bgcolor=black></td>

<?php
$frameDuration = ($timeline->shotStopFram e) - ($timeline->shotStartFrame );
$cellwidth = round(($frameDu ration * 650)/ $movieLengthTim eline);//round here

?>

<td width="<?php echo ($cellwidth); ?>" height="17" bgcolor=green></td>
<?php
$prevTime = ($timeline->shotStopFrame) ;
}
?>
[/PHP]

[code green]

PHP is assuming that movieLength is a constant because it is not a variable
[PHP]$movieLengthTim eline = (movieLength * 30);[/PHP] What is it meant to be?

[nma]

Hi

It is actually calling a javascripts function into a php code..but I am not sure how to write it

Thanks

[Atli]

Hi.

It is not possible to call Javascript functions in your PHP code, or PHP functions in Javascript code.
(Unless you use AJAX, but that's a whole other topic)

This is because the Javascript code is execute on the client's browsers (client-side) while the PHP code is executed on the server (server-side) before the code is sent to the browser.

The only way to have PHP call a Javascript function is to print the function call as Javascript code to the browser, but it can not directly interact with the Javascript code.

[Amzul]

var movieLength = getMovieLength("<?php echo $movie->duration?>");

[CODE=php]$movieLengthTim eline = (movieLength * 30);[/CODE]
u cant, (i am sure 99.9999% server / client)
its a js var, data from php. so just try do:

[CODE=php]$movieLengthTim eline = ($movie->duration * 30); [/CODE] if its possible

[Atli]

var movieLength = getMovieLength("<?php echo $movie->duration?>");

[CODE=php]$movieLengthTim eline = (movieLength * 30);[/CODE]
u cant, (i am sure 99.9999% server / client)
its a js var, data from php. so just try do:

[CODE=php]$movieLengthTim eline = ($movie->duration * 30); [/CODE] if its possible

That won't work, as the PHP $movie->duration variable is supposed to be run through the Javascript function and the result returned into PHP via the Javascript variable.

The easiest solution to this problem is to re-write the Javascript function as a PHP function.

[nma]

Hi All

I solve the problem...I write the functions again in php and put before the running lines code inside the php and it works

Is it ok if i put that php functions anywhere in php codes ?

Thanks